在select語句中調整oracle子查詢

Question

我有一個主表和一個參考表，如下所示。

WITH MAS as (
SELECT 10 as CUSTOMER_ID, 1 PROCESS_ID, 44 PROCESS_TYPE, 200 as AMOUNT FROM DUAL UNION ALL
SELECT 10 as CUSTOMER_ID, 1 PROCESS_ID, 44 PROCESS_TYPE, 250 as AMOUNT FROM DUAL UNION ALL
SELECT 10 as CUSTOMER_ID, 2 PROCESS_ID, 45 PROCESS_TYPE, 300 as AMOUNT FROM DUAL UNION ALL
SELECT 10 as CUSTOMER_ID, 2 PROCESS_ID, 45 PROCESS_TYPE, 350 as AMOUNT FROM DUAL 
), REFTAB as (
SELECT 44 PROCESS_TYPE, 'A' GROUP_ID FROM DUAL UNION ALL 
SELECT 44 PROCESS_TYPE, 'B' GROUP_ID FROM DUAL UNION ALL
SELECT 45 PROCESS_TYPE, 'C' GROUP_ID FROM DUAL UNION ALL 
SELECT 45 PROCESS_TYPE, 'D' GROUP_ID FROM DUAL
) SELECT ...

我的第一個正確運行的select語句是這樣的：

SELECT CUSTOMER_ID,
       SUM(AMOUNT) as AMOUNT1,
       SUM(CASE WHEN PROCESS_TYPE IN (SELECT PROCESS_TYPE FROM REFTAB WHERE GROUP_ID = 'A') 
                THEN AMOUNT ELSE NULL END) as AMOUNT2,
       COUNT(CASE WHEN PROCESS_TYPE IN (SELECT PROCESS_TYPE FROM REFTAB WHERE GROUP_ID = 'D') 
                  THEN 1 ELSE NULL END) as COUNT1
   FROM MAS
  GROUP BY CUSTOMER_ID

但是，為了解決性能問題，我將其更改為以下select語句：

SELECT CUSTOMER_ID,
       SUM(AMOUNT) as AMOUNT1,
       SUM(CASE WHEN GROUP_ID = 'A' THEN AMOUNT ELSE NULL END) as AMOUNT2,
       COUNT(CASE WHEN GROUP_ID = 'D' THEN 1 ELSE NULL END) as COUNT1
   FROM MAS A
   LEFT JOIN REFTAB B ON A.PROCESS_TYPE = B.PROCESS_TYPE
  GROUP BY CUSTOMER_ID

對於AMOUNT2和COUNT1列，值保持不變。 但是對於AMOUNT1 ，由於與參考表的AMOUNT1 ，該值被相乘。

我知道我可以在GROUP_ID上添加另外1個附加條件的左連接。 但這與使用子查詢沒有什么不同。

任何想法如何使查詢僅與1個左AMOUNT1一起工作，而又不乘AMOUNT1值？

Answer 1

通常的方法是在group by之前匯總值。 如果查詢的其余部分正確，則也可以使用條件聚合：

SELECT CUSTOMER_ID,
       SUM(CASE WHEN seqnum = 1 THEN AMOUNT END) as AMOUNT1,
       SUM(CASE WHEN GROUP_ID = 'A' THEN AMOUNT ELSE NULL END) as AMOUNT2,
       COUNT(CASE WHEN GROUP_ID = 'D' THEN 1 ELSE NULL END) as COUNT1
FROM MAS A LEFT JOIN
     (SELECT B.*, ROW_NUMBER() OVER (PARTITION BY PROCESS_TYPE ORDER BY PROCESS_TYPE) as seqnum
      FROM REFTAB B
     ) B
     ON A.PROCESS_TYPE = B.PROCESS_TYPE
GROUP BY CUSTOMER_ID;

這將忽略由聯接創建的重復項。

Answer 2

我知道我可以再添加1個附加GROUP_ID子句，再增加1個左聯接，但這與子查詢沒有什么不同。

您會感到驚訝。 在SELECT有2個左聯接而不是子查詢為優化器提供了更多優化查詢的方法。 我仍然會嘗試：

select m.customer_id,
       sum(m.amount) as amount1,
       sum(case when grpA.group_id is not null then m.amount end) as amount2,
       count(grpD.group_id) as count1
  from mas m
  left join reftab grpA
    on grpA.process_type = m.process_type
   and grpA.group_id = 'A'
  left join reftab grpD
    on grpD.process_type = m.process_type
   and grpD.group_id = 'D'
 group by m.customer_id

您也可以嘗試使用以下查詢，該查詢使用SUM()分析函數在連接之前計算amount1值，以避免出現重復值問題：

select m.customer_id,
       m.customer_sum as amount1,
       sum(case when r.group_id = 'A' then m.amount end) as amount2,
       count(case when r.group_id = 'D' then 'X' end) as count1
  from (select customer_id,
               process_type,
               amount,
               sum(amount) over (partition by customer_id) as customer_sum
          from mas) m
  left join reftab r
    on r.process_type = m.process_type
 group by m.customer_id,
          m.customer_sum

您可以測試兩個選項，然后查看哪個選項效果更好。

Answer 3

從原始查詢開始，簡單地用EXISTS語句替換IN查詢應該會大大提高。 另外，請注意將NULL相加，也許您的ELSE語句應該為0 ？

SELECT CUSTOMER_ID,
       SUM(AMOUNT) as AMOUNT1,
       SUM(CASE WHEN EXISTS(SELECT 1 FROM REFTAB WHERE REFTAB.GROUP_ID = 'A' AND REFTAB.PROCESS_TYPE = MAS.PROCESS_TYPE)
                THEN AMOUNT ELSE NULL END) as AMOUNT2,
       COUNT(CASE WHEN EXISTS(SELECT 1 FROM REFTAB WHERE REFTAB.GROUP_ID = 'D' AND REFTAB.PROCESS_TYPE = MAS.PROCESS_TYPE) 
                  THEN 1 ELSE NULL END) as COUNT1
   FROM MAS
  GROUP BY CUSTOMER_ID