如何將文件內容排序到列表中

Question

我需要一個解決方案來對文件進行排序，如下所示：

Super:1,4,6
Superboy:2,4,9

我的文件目前看起來像這樣：

Super:1
Super:4
Super:6

我需要幫助來跟蹤測驗中每個成員獲得的分數。 學校有三個班級，每個班級需要分別保存數據。

我的代碼如下：

className = className +(".txt")#This adds .txt to the end of the file so the user is able to create a file under the name of their chosen name.

file = open(className , 'a')   #opens the file in 'append' mode so you don't delete all the information
name = (name)
file.write(str(name + " : " )) #writes the information to the file
file.write(str(score))
file.write('\n')
file.close()    #safely closes the file to save the information

Answer 1

您可以使用dict對數據進行分組，特別是collections.OrderedDict，以保持原始文件中名稱的順序：

from collections import OrderedDict

with open("class.txt") as f:
    od = OrderedDict()
    for line in f:
        # n = name, s = score
        n,s = line.rstrip().split(":")
        # if n in dict append score to list 
        # or create key/value pairing and append
        od.setdefault(n, []).append(s)

只需將dict鍵和值寫入文件即可獲得所需的輸出，使用csv模塊為您提供漂亮的逗號分隔輸出。

from collections import OrderedDict
import csv
with open("class.txt") as f, open("whatever.txt","w") as out:
    od = OrderedDict()
    for line in f:
        n,s = line.rstrip().split(":")
        od.setdefault(n, []).append(s)
    wr = csv.writer(out)
    wr.writerows([k]+v for k,v in od.items())

如果要更新原始文件，可以寫入tempfile.NamedTemporaryFile並使用shutil.move替換原始文件 ：

from collections import OrderedDict
import csv
from tempfile import NamedTemporaryFile
from shutil import move

with open("class.txt") as f, NamedTemporaryFile("w",dir=".",delete=False) as out:
    od = OrderedDict()
    for line in f:
        n, s = line.rstrip().split(":")
        od.setdefault(n, []).append(s)
    wr = csv.writer(out)
    wr.writerows([k]+v for k,v in od.items())
# replace original file
move(out.name,"class.txt")

如果您有多個類，只需使用循環：

classes = ["foocls","barcls","foobarcls"]

for cls in classes:
    with open("{}.txt".format(cls)) as f, NamedTemporaryFile("w",dir=".",delete=False) as out:
        od = OrderedDict()
        for line in f:
            n, s = line.rstrip().split(":")
            od.setdefault(n, []).append(s)
        wr = csv.writer(out)
        wr.writerows([k]+v for k,v in od.items())
    move(out.name,"{}.txt".format(cls))

Answer 2

我會提供一些偽代碼來幫助你。

首先，您的數據結構應如下所示：

data = {'name': [score1, score2, score3]}

那么你應該遵循的邏輯應該是這樣的：

Read the file line-by-line
    if name is already in dict:
       append score to list. example: data[name].append(score)
    if name is not in dict:
       create new dict entry. example: data[name] = [score]

Iterate over dictionary and write each line to file