[英]How to implement single search form in yii2
Yii2有一個searchModel
來搜索GridView
每個字段。 是否可以在GridView
外部創建單個搜索字段,用戶可以在其中輸入關鍵字,並且在按下搜索按鈕時,結果將根據輸入的關鍵字顯示在GridView
。
CONTROLLER
public function actionIndex()
{
$session = Yii::$app->session;
//$searchModel = new PayslipTemplateSearch();
$PayslipEmailConfig = PayslipEmailConfig::find()->where(['company_id'=> new \MongoId($session['company_id'])])->one();
$payslipTemplateA = PayslipTemplate::find()->where(['company_id' => new \MongoId($session['company_id'])])->andwhere(['template_name' => 'A'])->one();
$payslipTemplateB = PayslipTemplate::find()->where(['company_id' => new \MongoId($session['company_id'])])->andwhere(['template_name' => 'B'])->one();
$pTemplateModel = PayslipTemplate::find()->where(['company_id' => new \MongoId($session['company_id'])])->all();
$user = User::find()->where(['_id' => new \MongoId($session['user_id'])])->one();
$module_access = explode(',', $user->module_access);
//$dataProvider = User::find()->where(['user_type' => 'BizStaff'])->andwhere(['parent' => new \MongoId($session['company_owner'])])->all();
$searchModel = new UserSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('index', [
'PayslipEmailConfig' => $PayslipEmailConfig,
'dataProvider' => $dataProvider,
'payslipTemplateA' => $payslipTemplateA,
'payslipTemplateB' => $payslipTemplateB,
'searchModel' => $searchModel,
]);
}
public function actionSearchresults($keyword)
{
$session = Yii::$app->session;
if ( $keyword == '') {
return $this->redirect(\Yii::$app->request->getReferrer());
} else {
$user = User::find()->where( [ '_id' => new \MongoId($id) ] )->one();
$searchModel = new PayslipTemplateSearch();
$payslipTemplateA = PayslipTemplate::find()->where(['company_id' => new \MongoId($session['company_id'])])->andwhere(['template_name' => 'A'])->one();
$payslipTemplateB = PayslipTemplate::find()->where(['company_id' => new \MongoId($session['company_id'])])->andwhere(['template_name' => 'B'])->one();
return $this->render('searchresults', [
'searchModel' => $searchModel,
'user' => $user,
'payslipTemplateA' => $payslipTemplateA,
'payslipTemplateB' => $payslipTemplateB,
]);
}
}
我在這里問了一個與此問題有關的問題: Yii2中的主要搜索表單
它不是由於Kartik的Select2
搜索下拉小部件中的一些復雜性。 現在我暫時切換到簡單的Yii2搜索字段。
視圖
echo $form->field($model, '_id')->textInput(array('placeholder' => 'search'))->label(false);
模型
<?php
namespace app\models;
use Yii;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use app\models\User;
/**
* UserSearch represents the model behind the search form about `app\models\User`.
*/
class UserSearch extends User
{
/**
* @inheritdoc
*/
public function rules()
{
return [
[[/*'_id',*/ 'creator_id'], 'integer'],
[['fname', 'lname', 'email', 'username', 'user_type'], 'safe'],
];
}
/**
* @inheritdoc
*/
public function scenarios()
{
// bypass scenarios() implementation in the parent class
return Model::scenarios();
}
/**
* Creates data provider instance with search query applied
*
* @param array $params
*
* @return ActiveDataProvider
*/
public function search($params)
{
$session = Yii::$app->session;
$query = User::find();
$query->where(['user_type' => 'BizStaff'])->andwhere(['parent' => new \MongoId($session['company_owner'])]);
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
$query->andFilterWhere([
'_id' => $this->_id,
'creator_id' => $this->creator_id,
]);
$query->andFilterWhere(['like', 'fname', $this->fname])
->andFilterWhere(['like', 'lname', $this->lname])
->andFilterWhere(['like', 'email', $this->email])
->andFilterWhere(['like', 'username', $this->username])
->andFilterWhere(['like', 'user_type', $this->user_type]);
return $dataProvider;
}
}
您對如何實施單一搜索有任何想法嗎? 這是一種更智能的搜索,因為它可以根據輸入的關鍵字搜索數據庫表中的所有內容。
編輯
當我搜索一個關鍵字,例如'hello'時,它會在輸入密鑰后給我這個url和錯誤:
網址:
HTTP://localhost/iaoy-dev/web/index.php R =工資單模板%2Fsearchresults&PayslipTemplateSearch%5B_id%5D =打招呼
錯誤信息:
錯誤請求(#400)缺少必需參數:id
救命。
我有同樣的問題,我的解決方案是:
模型
使用搜索參數擴展UserSearch模型
class UserSearch extends User
{
public $searchstring;
...
啟用傳遞變量
public function rules()
{
return [
...
[['searchstring'], 'safe'],
];
}
更改您的搜索方法(注意:搜索字段與orFilterWhere
結合,取決於您的需求)。
$query->orFilterWhere(['like', 'fname', $this->searchstring])
->orFilterWhere(['like', 'lname', $this->searchstring])
->orFilterWhere(['like', 'email', $this->searchstring])
->orFilterWhere(['like', 'username', $this->searchstring])
->orFilterWhere(['like', 'user_type', $this->searchstring]);
查看 (也可以是布局)
使用搜索輸入擴展您的表單。 您可以自己設置輸入字段的樣式,這只是一個示例:
<?php
/* @var $searchModel app\models\UserSearch */
echo $form->field($searchModel, 'searchstring', [
'template' => '<div class="input-group">{input}<span class="input-group-btn">' .
Html::submitButton('GO', ['class' => 'btn btn-default']) .
'</span></div>',
])->textInput(['placeholder' => 'Search']);
?>
調節器
發布表單后還要檢查$searchstring
的值。
public function actionIndex()
{
...
$searchModel = new UserSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
...
return $this->render('index', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
}
而已。
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