如何將子查詢用作存儲過程MySQL的一部分

Question

我正在嘗試創建一個過程（在phpMyAdmin中稱為例程），當前具有以下查詢：

BEGIN

INSERT INTO `users` (`username`, `password`, `email`, `user_role_id`,` date_registered`)
    VALUES (_username, _password, _email, (SELECT `ID` FROM `roles` WHERE `role_name` = _role) , _date);

END;

但這不起作用，我試圖將一個變量聲明為role_ID，這也沒有起作用，有人可以幫我解決這個問題嗎？

注意

您看到的參數（以下划線（ _開頭））都是phpMyAdmin例程創建器中使用的IN參數

編輯

我嘗試過的其他代碼是這樣的：

BEGIN

DECLARE role_id AS/*=*/ (SELECT `ID` FROM `roles` WHERE `role_name` = _role); /* tried both AS and = */

INSERT INTO `users` (`username`, `password`, `email`, `user_role_id`, `date_registered`)
    VALUES (_username, _password, _email, role_id, _date);

END;

還注意到DECLARE出現了一個小錯誤，將上面的代碼更改為：

BEGIN

DECLARE @role_id ;
SET @role_id = (SELECT `ID` FROM `roles` WHERE `role_name` = _role);

INSERT INTO `users` (`username`, `password`, `email`, `user_role_id`, `date_registered`)
    VALUES (_username, _password, _email, @role_id, _date);

END;

但是仍然沒有運氣

Answer 1

USE [FydaDB]
GO
/****** Object:  StoredProcedure [dbo].[CountryManagerReport]    Script Date: 5/25/2018 2:12:42 AM ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
ALTER PROCEDURE [dbo].[CountryManagerReport] 
    @FromDate datetime,
    @Todate datetime,
    @countryId int
AS
BEGIN
Select FirstName+ ' ' + MiddleName+ '' +  LastName as FullName ,Email,CNIC,((select CountryCode from Country where ID=FydaAdmin.CountryId)+ '-' +(select PhoneNo from Contacts where FydaAdminId=FydaAdmin.ID)) as Mobile,
(ZipCode+ ' ,' +[Address]+ ' ,' + (select Name from City where ID=FydaAdmin.CityId )+ ', ' +(select Name from States where ID=FydaAdmin.StateId )+ ', ' +(select Name from Country where ID=FydaAdmin.CountryId)
 ) as [Address]
 from FydaAdmin where CreatedDateTime  BETWEEN  @FromDate  and @Todate or CountryId=@countryId 
END

Answer 2

我已經解決了如何執行此操作-盡管未使用子查詢，但我具有以下存儲過程：

BEGIN

INSERT INTO `users` (`username`, `password`, `email`, `user_role_ID`, `date_registered`)
    VALUES (username, pwd, email, role, datenow);

END

以及此PHP函數和類可以使用：

class create_user
{
    public static function CreateUser($username, $password, $email, $role)
    {
        global $link;
        #region Get role id
        $role_q = "SELECT `ID` FROM `roles` WHERE `role_name` = '{$role}';";
        $role_rs = mysqli_fetch_row($link->query($role_q));
        $role = $role_rs[0];
        #endregion

        #region Create user
        $link->query("CALL sp_create_user('{$username}', '" . hash("sha256", $password) . "', '{$email}', '{$role}', '" . date("y-m-d H:i:s") . "')") ? $inserted = true : $inserted = false;
        #endregion

        #region check if user created
        if ($inserted)
        {
            return true;
        }
        else
        {
            return "User was not created. Either the username or email is already in use.";
        }
        #endregion
    }
}

如果有人可以通過子查詢來做到這一點，那將是正確的答案，因為它可行，但不是我所提問題的完整答案。

祝您編程愉快！