[英]How do I get the business days in a week with PHP given the range and current week as params?
[英]How to get every specific days of week within given date range in PHP?
這給了我日期范圍內的每個星期一日期。
問題:如何獲得每周一和周五的每周一?
$start_date = date('Y-m-d');
$end_date = date('Y-m-d', strtotime($start_date . ' + 1 MONTH'));
for(
$i = strtotime('Monday', strtotime($start_date));
$i <= strtotime($end_date);
$i = strtotime('+1 WEEK', $i)
) {
echo date('Y-m-d', $i). '<br>';
}
我的更新:
$my_dates = [];
for(
$i = strtotime($start_date);
$i <= strtotime($end_date);
$i = strtotime('+1 DAY', $i)
) {
if(in_array(date('N', $i), array(1, 5))) {
$my_dates[] = date('Y-m-d', $i);
}
}
var_dump($my_dates);
看看名為When的庫,它是“PHP 5.3+的日期/日歷遞歸庫” 。
讓我們說下個月的MF時間表:
$now = new DateTime('NOW');
$till = clone $now;
$till->modify('+1 month');
$r = new When();
$r->startDate($now)
->freq("weekly")
->until($till)
->byday(array('MO', 'FR'))
->generateOccurrences();
$occurrences = $r->occurrences;
如果我沒錯,你可以簡單地使用for
循環
$start = "2015-09-01";
$end = date('Y-m-d', strtotime("$start +1 months"));
$period = floor((strtotime($end) - strtotime($start))/(24*60*60));
for($i = 0; $i < $period; $i++){
if(in_array(date('l',strtotime("$start +$i day")),["Monday","Friday"]))
echo date('l d M, Y',strtotime("$start +$i day"))."\n";
}
輸出:
Friday 04 Sep, 2015
Monday 07 Sep, 2015
Friday 11 Sep, 2015
Monday 14 Sep, 2015
Friday 18 Sep, 2015
Monday 21 Sep, 2015
Friday 25 Sep, 2015
Monday 28 Sep, 2015
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