[英]CakePHP 3.1: Save in joinTable same foreign key but different _joinData
我在要保存的模型中有此關聯:
$this->belongsToMany('Tags', [
'className' => 'Tags',
'joinTable' => 'tags_associations',
'foreignKey' => 'foreign_key',
'targetForeignKey' => 'tag_id'
]);
我想將具有相同Tags.id
但具有不同_joinData
值的tags_associations
2記錄保存在關聯表中。 這是一個例子
object(Companies\Model\Entity\Company) {
'id' => (int) 765,
'tags' => [
(int) 0 => object(Cake\ORM\Entity) {
'id' => (int) 2,
'tag_category_id' => (int) 1,
'level' => (int) 1,
'parent_id' => (int) 1,
'lft' => (int) 2,
'rght' => (int) 135,
'tag_name' => 'Abbigliamento',
'slug' => 'abbigliamento',
'description' => null,
'created' => object(Cake\I18n\Time) {
'time' => '2015-10-04T17:56:02+0200',
'timezone' => 'Europe/Rome',
'fixedNowTime' => false
},
'modified' => object(Cake\I18n\Time) {
'time' => '2015-10-05T10:03:53+0200',
'timezone' => 'Europe/Rome',
'fixedNowTime' => false
},
'_joinData' => object(Cake\ORM\Entity) {
'model' => 'Companies',
'tag_group_id' => (int) 2,
'[new]' => true,
'[accessible]' => [
'*' => true
],
'[dirty]' => [
'model' => true,
'tag_group_id' => true
],
'[original]' => [],
'[virtual]' => [],
'[errors]' => [],
'[repository]' => 'TagsAssociations'
},
'[new]' => false,
'[accessible]' => [
'*' => true
],
'[dirty]' => [
'_joinData' => true
],
'[original]' => [
'_joinData' => object(Cake\ORM\Entity) {
'model' => 'Companies',
'tag_group_id' => (int) 1,
'[new]' => true,
'[accessible]' => [
'*' => true
],
'[dirty]' => [
'model' => true,
'tag_group_id' => true
],
'[original]' => [],
'[virtual]' => [],
'[errors]' => [],
'[repository]' => 'TagsAssociations'
}
],
'[virtual]' => [],
'[errors]' => [],
'[repository]' => 'Tags'
},
(int) 1 => object(Cake\ORM\Entity) {
'id' => (int) 2,
'tag_category_id' => (int) 1,
'level' => (int) 1,
'parent_id' => (int) 1,
'lft' => (int) 2,
'rght' => (int) 135,
'tag_name' => 'Abbigliamento',
'slug' => 'abbigliamento',
'description' => null,
'created' => object(Cake\I18n\Time) {
'time' => '2015-10-04T17:56:02+0200',
'timezone' => 'Europe/Rome',
'fixedNowTime' => false
},
'modified' => object(Cake\I18n\Time) {
'time' => '2015-10-05T10:03:53+0200',
'timezone' => 'Europe/Rome',
'fixedNowTime' => false
},
'_joinData' => object(Cake\ORM\Entity) {
'model' => 'Companies',
'tag_group_id' => (int) 2,
'[new]' => true,
'[accessible]' => [
'*' => true
],
'[dirty]' => [
'model' => true,
'tag_group_id' => true
],
'[original]' => [],
'[virtual]' => [],
'[errors]' => [],
'[repository]' => 'TagsAssociations'
},
'[new]' => false,
'[accessible]' => [
'*' => true
],
'[dirty]' => [
'_joinData' => true
],
'[original]' => [
'_joinData' => object(Cake\ORM\Entity) {
'model' => 'Companies',
'tag_group_id' => (int) 1,
'[new]' => true,
'[accessible]' => [
'*' => true
],
'[dirty]' => [
'model' => true,
'tag_group_id' => true
],
'[original]' => [],
'[virtual]' => [],
'[errors]' => [],
'[repository]' => 'TagsAssociations'
}
],
'[virtual]' => [],
'[errors]' => [],
'[repository]' => 'Tags'
}
],
}
在我的示例中,tags_association表中僅保留第二個實體。
您可以使用http://book.cakephp.org/3.0/en/orm/associations.html#using-the-through-option中的“ through
選項
class StudentsTable extends Table
{
public function initialize(array $config)
{
$this->belongsToMany('Courses', [
'through' => 'CourseMemberships',
]);
}
}
class CoursesTable extends Table
{
public function initialize(array $config)
{
$this->belongsToMany('Students', [
'through' => 'CourseMemberships',
]);
}
}
class CoursesMembershipsTable extends Table
{
public function initialize(array $config)
{
$this->belongsTo('Students');
$this->belongsTo('Courses');
}
}
現在, CourseMemberships
模型是一個單獨的模型,您可以創建CourseMemberships
模型。
最后,我與另一個協會解決了
$this->belongsToMany('Tags', [
'className' => 'Tags',
'joinTable' => 'tags_associations',
'foreignKey' => 'foreign_key',
'targetForeignKey' => 'tag_id',
]);
$this->belongsToMany('TagsSecondary', [
'className' => 'Tags',
'joinTable' => 'tags_associations',
'foreignKey' => 'foreign_key',
'targetForeignKey' => 'tag_id',
'saveStrategy' => 'append'
]);
首先,我使用標簽關聯保存tag_group_id = 1
的標簽,之后使用tag_group_id = 2
保存具有tag_group_id = 1
的標簽,並附加為saveStrategy 。
您可以在控制器中加載模型
$this->loadModel('tagAssociations');
然后,您可以從該表中創建新實體,對其進行修補並最終保存。
//saving tags
$tagAssociation = $this->tagAssociations->newEntity();
//$handling $data
$tagAssociation = $this->tagAssociations->patchEntity($tagAssociation , $data);
$this->tagAssociations->save($tagAssociation );
這是我發現的最佳解決方案。
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