[英]>>> URI is not hierarchical
抱歉,我是新來的,但我有問題,希望有人能幫助我解決。
這段代碼在eclipse中運行完美,但是編譯后說:
java.lang.IllegalArgumentException:URI不是分層的
任何幫助將是適當的,謝謝!
public void loadMods(String pkg) throws IllegalAccessException, IllegalArgumentException, InvocationTargetException, InstantiationException {
List<Class<?>> classes = getClasses(pkg);
for(Class<?> c : classes) {
for (Method m : c.getMethods()) {
Object o = null;
o = c.newInstance();
if (m.getName().contains("load")) {
m.setAccessible(true);
m.invoke(o);
}
}
}
}
public static List<Class<?>> getClasses(String pkg) {
String pkgname = pkg;
List<Class<?>> classes = new ArrayList<Class<?>>();
File directory = null;
String fullPath;
String relPath = pkgname.replace('.', '/');
URL resource = ClassLoader.getSystemClassLoader().getResource(relPath);
if (resource == null) {
throw new RuntimeException("No resource for " + relPath);
}
fullPath = resource.getFile();
try {
directory = new File(resource.toURI());
} catch (URISyntaxException e) {
throw new RuntimeException(pkgname + " (" + resource + ") invalid URL / URI.", e);
} catch (IllegalArgumentException e) {
directory = null;
}
if (directory != null && directory.exists()) {
String[] files = directory.list();
for (int i = 0; i < files.length; i++) {
if (files[i].endsWith(".class")) {
String className = pkgname + '.' + files[i].substring(0, files[i].length() - 6);
try {
classes.add(Class.forName(className));
} catch (ClassNotFoundException e) {
throw new RuntimeException("ClassNotFoundException loading " + className);
}
} else {
String pkgnamex = pkgname + '.' + files[i];
List<Class<?>> classesx = new ArrayList<Class<?>>();
File directoryx = null;
String fullPathx;
String relPathx = pkgnamex.replace('.', '/');
URL resourcex = ClassLoader.getSystemClassLoader().getResource(relPathx);
if (resourcex == null) {
throw new RuntimeException("No resource for " + relPathx);
}
fullPathx = resourcex.getFile();
try {
directoryx = new File(resourcex.toURI());
} catch (URISyntaxException e) {
throw new RuntimeException(pkgnamex + " (" + resourcex + ") invalid URL / URI.", e);
} catch (IllegalArgumentException e) {
directoryx = null;
}
if (directoryx != null && directoryx.exists()) {
String[] filesx = directoryx.list();
for (int ix = 0; ix < filesx.length; ix++) {
if (filesx[ix].endsWith(".class")) {
String classNamex = pkgnamex + '.' + filesx[ix].substring(0, filesx[ix].length() - 6);
try {
classes.add(Class.forName(classNamex));
} catch (ClassNotFoundException e) {
throw new RuntimeException("ClassNotFoundException loading " + classNamex);
}
}
}
}
}
}
}
return classes;
}
當您在Eclipse中運行代碼時,它會使用已編譯的類(默認情況下位於“目標”文件夾中)。 但是,如果通常從外部運行代碼,則使用Eclipse創建的JAR文件。
當引用由鏈接的問題解釋的JAR中的內容時,就會出現此問題。
簡而言之:文件系統中的URI在語法上是正確的。 將某些內容引用到JAR中的URI不再是有效的URI。
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