[英]SQL - Table sort by events
我有一張這樣的桌子:
+--------+--------+
| userid | events |
+--------+--------+
| 1 | blog |
| 2 | blog |
| 1 | site |
| 1 | move |
| 2 | move |
| 3 | blog |
| 2 | blog |
+--------+--------+
我想顯示所有參加我作為參數傳遞的事件的用戶。
示例:所有參與“博客”和“移動”的用戶
知道用戶可以多次參加某個事件。
謝謝你的幫助
select userid
from your_table
where events in ('blog','move')
group by userid
having count(distinct events) = 2
如果您要檢查3個事件,請使用
having count(distinct events) = 3
SELECT DISTINCT userid
FROM table_name
WHERE events = 'blog'
AND userid IN
(
SELECT DISTINCT userid
FROM table_name
WHERE events = 'move'
)
嘗試這個
select a.userid
from tablename a join tablename b
on a.userid = b.userid
where a.events='blog' and b.events='move';
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