顯示兩個表中的數據-Codeigniter中的一對多關系

Question

我有兩個表：

Table 1 -- rps_users:

id
membership_number
family_name
first_name
email_address
staff (staff column having values Y and N)

Table 2 -- rps_volunteer_score:
volunteer_id
registration_assessor
interviewer
professional_registration_advisor

第一個表中的id列包含與第二個表中的volunteer_id id列相同的值。 每個用戶可以具有多個registration_assessor ， interviewer和professional_registration_advisor值。這些列的可能值為0-4 。

我想要在瀏覽器記錄中顯示的內容是在staff列中值為N用戶，其格式如下：

membership_number:000
family_name:Name1
first_name:Name2
email_address:a@b.com
Type:Interviwer/Assessor/Registrar/PRA/Moderator(If the user have multuple role display all ie, Interviewer,Assessor)

根據以下條件對類型列進行重新記錄

    if( $interviewer!="" && $interviewer <= 4 )echo "Interviewer";
    if($registration_assessor !="" && $registration_assessor >= 2 &&     $registration_assessor <= 4 )echo "Assessor";
    if($registration_assessor !="" && $registration_assessor >= 3 && $registration_assessor <= 4)echo "Moderator";
    if($registration_assessor !="" && $registration_assessor == 4 ) echo "Registrar";
    if($professional_registration_advisor !="" && $professional_registration_advisor== 1)echo "PRA";

這是我的模型功能

    public function get_volunteers_list($condition)
{

    $this->db->select("u.id,u.membership_number,u.family_name,u.first_name,u.email_address,vs.volunteer_id,vs.registration_assessor, vs.interviewer,vs.professional_registration_advisor");
    $this->db->from(self::$tbl_name . " as u");
    $this->db->join(Volunteer_score::$tbl_name . " as vs", "u.id = vs.volunteer_id","left");
    $this->db->where($condition);
    $query = $this->db->get(); 
    return $query->result();

}

這是我的控制器代碼

    $volunteer_list = $this->Users->get_volunteers_list(array("u.staff"=>'N'));
    $this->data["volunteer_list"] = $volunteer_list;

這是我的查看代碼

    <?php
        if($volunteer_list)
        {
        foreach($volunteer_list as $volunteer)
        {

            echo "<td>{$volunteer->membership_number}</td>";
echo "<td>{$volunteer->family_name}, {$first_name}</td>";
echo "<td>{$volunteer->email_address}</td>";
echo "<td>";(Here i want to display the type of the user)
//Following is the condition for "TYPE"
/*if( $interviewer!="" && $interviewer <= 4 )
{
    echo "Interviewer"; 


}

if($registration_assessor !="" && $registration_assessor >= 2 && $registration_assessor <= 4 )
{
    echo "Assessor";


}
if($registration_assessor !="" && $registration_assessor >= 3 && $registration_assessor <= 4)
{
    echo "Moderator";


}
if($registration_assessor !="" && $registration_assessor == 4 )
{
    echo "Registrar";


}
if($professional_registration_advisor !="" && $professional_registration_advisor == 1)
{
    echo "PRA";


}*/
echo"</td>";
echo "</tr>";
        }
        }
        ?>

Answer 1

匯編的sql看起來像：

SELECT u.id, u.membership_number, u.family_name, u.first_name, u.email_address, 
GROUP_CONCAT(vs.registration_category) AS type
FROM volunteers_list as u
LEFT JOIN Volunteer_score as vs ON(u.id = vs.volunteer_id)
GROUP BY u.id;

並且您將獲得一行，其registration_categorys以逗號分隔