如何在 Swing 運行時在 JTable 中添加行

Question

目前，我正在嘗試將行添加到 java swing 中的 JTable 並獲得以下輸出。 顯示 java.lang.someerror 的第一個單元格附加 Null

這是單元格顯示錯誤的輸出

，我無法在表中附加字符串。 收到類似的錯誤

無法將字符串轉換為對象

需要插入代碼中的表（String Object [] []）如下

  class SimpleTableExample
                extends     JFrame
 {
// Instance attributes used in this example
private JPanel      topPanel;
private JTable table;
private JScrollPane scrollPane;

// Constructor of main frame
public SimpleTableExample()
{
    // Set the frame characteristics
    setTitle( "Simple Table Application" );
    setSize( 1100, 150 );
    setBackground( Color.gray );

    // Create a panel to hold all other components
    topPanel = new JPanel();
    topPanel.setLayout( new BorderLayout() );
    getContentPane().add( topPanel );

    // Create columns names
    String columnNames[] = { " Date & Time", "VRP", "VYP", "VBP", "CRP","CYP","CBP","PO","BM","ARM","WT","RH","CNT","BCC","W","F","L","status"};

    // Create some data
    String dataValues[][] =
    {
            { null, null, null , null, null, null, null, null , null, null,null, null, null , null, null, null, null, null },
            { null, null, null , null, null, null, null, null , null, null,null, null, null , null, null, null, null, null },
            { null, null, null , null, null, null, null, null , null, null,null, null, null , null, null, null, null, null },
            { null, null, null , null, null, null, null, null , null, null,null, null, null , null, null, null, null, null },
            { null, null, null , null, null, null, null, null , null, null,null, null, null , null, null, null, null, null },
            { null, null, null , null, null, null, null, null , null, null,null, null, null , null, null, null, null, null },

    };

        String Object[][] = {{"85", "85","85","85","85","85","85","85","85","85","85","85","85","85","85","85","85","85"}};
        DefaultTableModel dm = new DefaultTableModel(0,0);
        dm.setColumnIdentifiers(columnNames);

        // Create a new table instance
        table = new JTable(dm);

        TableColumn column = null;
        for(int i =0; i<18; i++){
            column =  table.getColumnModel().getColumn(i);
            if(i==0)
            {
                column.setPreferredWidth(100);
            }
            else{
                column.setPreferredWidth(40);
            }
        }
        table.setModel(dm);

       /* i have tried to use vector for insertion didn't work  
        Vector <Object> data = new Vector <Object>();
        data.add(null);
        data.add(null);
        dm.addRow(data); */

((DefaultTableModel) ((JTable) table).getModel()).addRow(new Object[]{});  //for this code row got inserted with some error displaying in first cell

// Add the table to a scrolling pane
scrollPane = new JScrollPane(table);
topPanel.add( scrollPane, BorderLayout.CENTER );


  }

    // Main entry point for this example
    public static void main( String args[] )
    {
        // Create an instance of the test application
        SimpleTableExample mainFrame    = new SimpleTableExample();
        mainFrame.setVisible( true );
    }
}


       ((DefaultTableModel) ((JTable) table).getModel()).addRow(new Object[]{"85","85","85","85","85","85","85","85","85","85","85","85","85","85","85","85","85","85"});

如果我使用它，則會出現此錯誤...

• 類型不匹配：無法從 String 轉換為 Object

請任何人幫助解決這個問題

Answer 1

構造函數要求您提供一個使用附加大括號聲明的 Object 數組。 我懷疑您使用的是String[]而不是Object[][] ：

Object[][] defaultValues={
            {"content1"},
            {"content2"}
        };

使用構造函數new DefaultTableModel(Object[][] data,Object[] columnames);對我有用 .