插入SQL表或更新記錄（如果存在）

Question

我想在數據庫表中添加一行，但如果存在具有相同唯一鍵的行，我想更新該行。

這是我的查詢：

$query = "INSERT INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('$audit_no','$form_details_subquestion_id','$form_details_section_id','$mark') 
ON DUPLICATE KEY UPDATE mark = VALUES($mark)";

但是，它將繼續插入新的記錄。 假設audit_section_id, form_details_subquestion_id, form_details_section_id是唯一鍵。 如果audit_section_id, form_details_subquestion_id, form_details_section_id存在audit_section_id, form_details_subquestion_id, form_details_section_id會將新記錄插入數據庫; 同時更新記錄。

我也試過這個：

REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_‌​details_section_id`,`mark`)
VALUES ('$audit_no','$form_details_subquestion_id','$form_details_section_id','$mark')

我不確定是我的代碼的for循環問題。

    for ($i=0; $i < ($_POST['count']); $i++)
{
    $form_details_subquestion_id    = $_POST['form_details_subquestion_id'][$i];
    $form_details_section_id        = $_POST['form_details_section_id'][$i];
    $mark                           = $_POST['mark'][$i];
    $remark                         = $_POST['remark'][$i]; 


    //$query = "INSERT INTO `table` (`id`, `name`, `email`) VALUES (' ".$_POST['id']." ', ' ".$_POST['name']." ', ' ".$_POST['email']." ')";    

    $query = "REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`)
    VALUES ('$audit_no','$form_details_subquestion_id','$form_details_section_id','$mark')";
    $result = $db->query($query);
}

我正在使用for循環來插入所有數據。

這是echo $ query的輸出;

  REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','89','1','1.00')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','86','1','1.00')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','87','1','1.00')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','88','1','1.00')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','85','1','1.00')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','83','1','1.00')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','84','1','1.00')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','81','1','1.00')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','82','1','1.00')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','98','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','99','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','100','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','101','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','102','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','96','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','97','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','90','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','91','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','92','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','93','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','94','1','2')
REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','95','1','2')

SQL表

   CREATE TABLE IF NOT EXISTS `audit_section_markrecord` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `audit_section_id` int(10) unsigned NOT NULL,
  `form_details_subquestion_id` int(10) unsigned NOT NULL,
  `form_details_section_id` int(10) unsigned NOT NULL,
  `mark` decimal(5,2) unsigned NOT NULL,
  `dateofmodify` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
  PRIMARY KEY (`id`)
)

Answer 1

編輯完最后一個問題后編輯：

你在桌子上有這個：

`id` int(11) NOT NULL AUTO_INCREMENT,
....
 PRIMARY KEY (`id`)

你的id （PRIMARY KEY）是自動增量的，你的問題是：

我想在數據庫表中添加一行，但如果存在具有相同唯一鍵的行，我想更新該行。

使用您的查詢，您永遠不會擁有相同的id因為您從未在查詢中設置id值，您的查詢是：

REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`) VALUES ('602633','95','1','2')

如果您沒有在查詢中設置id值，數據庫系統會自動自動增加id列值，您永遠不必更新行。

---

這應該是您的查詢：

$query = "REPLACE INTO audit_section_markrecord(`audit_section_id`,`form_details_subquestion_id`,`form_details_section_id`,`mark`)
    VALUES ('$audit_no','$form_details_subquestion_id','$form_details_section_id','$mark')";

但是audit_section_id ， form_details_subquestion_id和form_details_section_id列值必須與要替換的行的現有行的值匹配; 否則，插入一行。

您可以在以下網址閱讀更多

http://dev.mysql.com/doc/refman/5.7/en/replace.html

例：

考慮以下CREATE TABLE語句創建的表：

CREATE TABLE test (
  id INT UNSIGNED NOT NULL AUTO_INCREMENT,
  data VARCHAR(64) DEFAULT NULL,
  ts TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  PRIMARY KEY (id)
);

當您創建此表並運行mysql客戶端中顯示的語句時，結果如下：

mysql> REPLACE INTO test VALUES (1, 'Old', '2014-08-20 18:47:00');
Query OK, 1 row affected (0.04 sec)

mysql> REPLACE INTO test VALUES (1, 'New', '2014-08-20 18:47:42');
Query OK, 2 rows affected (0.04 sec)

mysql> SELECT * FROM test; 
+----+------+---------------------+
| id | data | ts                  |
+----+------+---------------------+
|  1 | New  | 2014-08-20 18:47:42 |
+----+------+---------------------+
1 row in set (0.00 sec)

現在，如果你創建一個幾乎與第一個表相同的第二個表，除了主鍵現在覆蓋2列，如此處所示（ PRIMARY KEY (id, ts) ）：

CREATE TABLE test2 (
  id INT UNSIGNED NOT NULL AUTO_INCREMENT,
  data VARCHAR(64) DEFAULT NULL,
  ts TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  PRIMARY KEY (id, ts)
);

當您在test2上運行與原始（第一個）測試表上相同的兩個REPLACE語句時，我們獲得了不同的結果：

mysql> REPLACE INTO test2 VALUES (1, 'Old', '2014-08-20 18:47:00');
Query OK, 1 row affected (0.05 sec)

mysql> REPLACE INTO test2 VALUES (1, 'New', '2014-08-20 18:47:42');
Query OK, 1 row affected (0.06 sec)

mysql> SELECT * FROM test2;
+----+------+---------------------+
| id | data | ts                  |
+----+------+---------------------+
|  1 | Old  | 2014-08-20 18:47:00 |
|  1 | New  | 2014-08-20 18:47:42 |
+----+------+---------------------+
2 rows in set (0.00 sec)

這是因為，當在test2上運行時，id和ts列值必須與要替換的行的現有行的值匹配; 否則，插入一行。