[英]MySQL query the same table with two date fields and group by same ID
我很難按照需要的方式從數據庫獲取結果,這是我的表:
+----+---------------------+---------------------+-----------+------------+--------+
| id | opendate | closedate | openprice | closeprice | sameid |
+----+---------------------+---------------------+-----------+------------+--------+
| 1 | 2015-09-20 19:17:52 | NULL | 10 | NULL | 20 |
| 2 | NULL | 2015-09-20 20:17:00 | NULL | 35 | 20 |
| 3 | 2015-09-15 19:17:52 | NULL | 15 | NULL | 10 |
| 4 | NULL | 2015-09-16 20:17:00 | NULL | 25 | 10 |
+----+---------------------+---------------------+-----------+------------+--------+
我需要像這樣按列sameid
分組的所有行:
+----+---------------------+---------------------+-----------+------------+--------+
| id | opendate | closedate | openprice | closeprice | sameid |
+----+---------------------+---------------------+-----------+------------+--------+
| 1 | 2015-09-20 19:17:52 | 2015-09-20 20:17:00 | 10 | 35 | 20 |
| 3 | 2015-09-15 19:17:52 | 2015-09-16 20:17:00 | 15 | 25 | 10 |
+----+---------------------+---------------------+-----------+------------+--------+
到目前為止,這是我嘗試過的:
(SELECT * FROM table WHERE opendate >= '2015-08-08 00:00:01') UNION (SELECT * FROM table WHERE closedate <= '2015-10-15 23:59:59')
我可以獲取所有行,但無法找到一種按sameid
分組的sameid
,我嘗試使用GROUP BY sameid
失敗。
希望你們能幫助我
謝謝
UPDATE該表是很早以前設計的(不是我設計的),並且存儲的信息太多,我也不允許重新設計數據庫架構。
如果您的表格格式完全符合您的描述,那么應該可以:
SELECT id,MAX(opendate),MAX(closedate),MAX(openprice),MAX(closeprice),sameid FROM table GROUP BY sameid;
但是,我認為您應該重新設計數據庫架構,將打開信息和關閉信息分成兩行(它們可以在2個表中或在同一表中)。 與嘗試一些解決方法相比,與您合作會更好。
問候,
嘗試這個
SELECT t1.opendate,t2.closedate,t1.openprice,t2.closeprice從`table` t1 JOIN`table` t2 ON t2.sameid = t1.sameid哪里t1.opendate> ='2015-08-08 00:00: 01'AND t2.closedate <='2015-10-15 23:59:59'AND t1.opendate不為空AND t2.closedate不為空
這將產生您的確切輸出。
SELECT
MIN(id) as id,
MAX(open_date) as open_date,
MAX(close_date) as close_date,
MAX(open_price) as open_price,
MAX(close_price) as close_price,
sameid
FROM
`table`
GROUP BY
sameid
ORDER BY id ASC
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