Python：另存為字符串時，保存數字錯誤

Question

我的代碼有問題，在這里：

correct = 0

grade_book = {}
File = open('Test.txt', 'r')
for line in File:
     name, scores = line.split(':')
     grade_book[name] = scores.strip()
File.close()
print(grade_book)

name = input("Name: ")
if name in grade_book.keys():
    grade_book[name] += ',' + correct
else:
    grade_book[name] = correct

File = open('Test.txt', 'w')
for name, scores in grade_book.items():
    out_line = str(name) + ':' + str(scores) + "\n"
    File.write(out_line)

File.close()

問題是它給出了錯誤說明：

TypeError：無法將“ int”對象隱式轉換為str

當程序嘗試將“正確”保存為文件中的現有名稱時，就會在程序中發生這種情況。 我嘗試使用以下方法解決此問題：

    name = input("Name: ")
if name in grade_book.keys():
    grade_book[name] += ',' + str(correct)
else:
    grade_book[name] = correct

但是，這樣做的問題是，盡管將“正確”分配給大於0的數字（例如8），但打印到文件的數字始終為0。另一方面，它確實會像以前一樣給出錯誤，只是上面的問題。

有什么解決辦法嗎？

是的，我可能在這里錯過了一些明顯的東西。

“正確”的代碼：

def mainLoop():
    global count
    global correct
    Num1 = randint(1, 10)
    Num2 = randint(1,10)
    Operand= randint(1,3)

    if Operand == 1:
        question = str(Num1) + " + " + str(Num2) + " = "
        answer = Num1 + Num2
    elif Operand == 2:
        question = str(Num1) + " - " + str(Num2) +" = "
        answer = Num1 - Num2
    else:
        question = str(Num1) + " x " + str(Num2) + " = "
        answer = Num1 * Num2

    userAnswer = int(input(question))
    if userAnswer == answer:
        correct += 1

猜猜我將發布整個代碼以供參考：

from random import randint
import time
count = 0
correct = 0

def mainLoop():
   global count
   global correct
   Num1 = randint(1, 10)
   Num2 = randint(1,10)
   Operand= randint(1,3)

   if Operand == 1:
       question = str(Num1) + " + " + str(Num2) + " = "
        answer = Num1 + Num2
   elif Operand == 2:
       question = str(Num1) + " - " + str(Num2) +" = "
       answer = Num1 - Num2
   else:
       question = str(Num1) + " x " + str(Num2) + " = "
       answer = Num1 * Num2

 userAnswer = int(input(question))
 if userAnswer == answer:
  correct += 1



grade_book = {}
File = open('Test.txt', 'r')
for line in File:
    name, scores = line.split(':')
   grade_book[name] = scores.strip()
File.close()
print(grade_book)

name = input("Name: ")
if name in grade_book.keys():
   grade_book[name] += ',' + str(correct)
else:
   grade_book[name] = str(correct)

File = open('Test.txt', 'w')
for name, scores in grade_book.items():
    out_line = str(name) + ':' + str(scores) + "\n"
    File.write(out_line)

File.close()

 while count < 10:
    mainLoop()
    count += 1

快了嗎，可能是錯的

文本文件示例： Test:1,5 John:1,0

Answer 1

將分數寫入文件后，您正在運行mainLoop ，因此該文件將不包含正確的分數。 只需將詢問問題的代碼移動10遍（ while count < 10等等）到將分數寫到grade_book的代碼grade_book （ if name in grade_book.keys():等等）。

您可能會發現避免使用全局變量會有所幫助。 取而代之的是，您可以具有一個根據用戶是否正確響應而返回True或False的問題函數，然后我們僅使用sum來計算正確和錯誤的響應。

from random import randint
import time

def question():
   a = randint(1, 10)
   b = randint(1,10)
   operand= randint(1,3)

   if operand == 1:
       sign = '+'
       answer = a + b
   elif operand == 2:
       sign = '-'
       answer = a - b
   else:
       sign = 'x'
       answer = a * b

   user_answer = int(input('{} {} {} = '.format(a, sign, b)))
   return user_answer == answer # returns True if correct, False if not

grade_book = {}
with open('Test.txt', 'r') as file:
    for line in file:
        name, scores = line.split(':')
        grade_book[name] = scores.strip()
print(grade_book)

name = input("Name: ")

# Ask a question 10 times and sum up the correct responses
# (This works because sum counts True as 1 and False as 0)
correct = sum(question() for _ in range(10)) 

if name in grade_book.keys():
   grade_book[name] += ',' + str(correct)
else:
   grade_book[name] = str(correct)

with open('Test.txt', 'w') as file:
    for name, scores in grade_book.items():
        file.write('{}:{}\n'.format(name, scores))

Answer 2

在grade_book[name] = correct您可以分配整數值correct 。 因此應該是：

name = input("Name: ")
if name in grade_book.keys():
    grade_book[name] += ',' + str(correct)
else:
    grade_book[name] = str(correct)

而且您對“正確”不做任何事情。 總是0。