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根據選擇值存儲表單輸入字段嗎?

[英]Store form input fields based on select value?

每當用戶訪問注冊頁面時,以及當他選擇自己的大學但未找到他的大學時,都有“其他”選項...

當他單擊“其他”時,將顯示另一個輸入字段,指出要指定您的大學。現在的問題是,如果他從選擇選項中選擇他的大學,那么我不想在數據庫中存儲“其他”值,則應該插入該值,但是如果他選擇“其他”選項,那么他在“指定”輸入中寫入的值應存儲在數據庫中

這是我的代碼

   <select class="job-purpose" name="college" id="college" >
   <option selected="selected" value="">-</option>
   <option value="1">
   NID - National Institute Of Design</option>
   <option value="2">
   NIFT - National Institute Of fashion Technology</option>
   <option value="3">
   Pearl Academy Of Fashion</option>
   <option value="4">
   SOFT - School Of Fashion Technology</option>
   <option value="5">
   Srishti Institute Of Design</option>
   <option value="6">
   MITID</option>
   <option value="7">
   Arch Academy Of Design</option>
   <option value="8">
   Satyam Fashion Institute</option>
   <option value="9">
   NIIFT</option>
  <option value="10">
  UID - United World Institute Of Design</option>
  <option value="11">
  International College Of Fashion </option>
  <option value="12">
  Raffles</option>

  <option value="other">
  other</option>
   </select>

這是更改選項代碼

    <div class="form-group" style="display:none;" id="coll">
    <div class="col-md-12">
    <div class="label-wrapper">
    <label class="control-label">College <span 
    class="vd_red">*</span></label>
    </div>

     <input type="text" name="coll" id="col" 
     placeholder="College Name">
     </div>
     </div>

這是Javascript代碼

    < script type="text/javascript" >
 $('#college').change(function(){
  selection = $(this).val();    
   switch(selection)
   { 
   case 'other':
       $('#coll').show();
       break;
   default:
       $('#coll').hide();
       break;
   }
   });
 < /script >

PHP部分

    if(empty($looking)or empty($profession) or empty($experience)or    
    empty($current)or empty($state)or empty($jobtype)or empty($about)){ 

    if($college == 'others'){
    $coll= $_POST['coll'];
     unset($_POST['college']);
    $college= $coll;
     }
<?php
        $college = $_POST['college'];
        $coll = $_POST['coll'];
//this below line checks for is college selected and checks for the value selected not the "other" option
        if (isset($collage) && $collage != 'other') {
            //run your database query hear
        }elseif (isset($coll)) { //this line checks for the inputfiled coll isset if yes go to next line
            //run your database query hear
        }
    ?>

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