提交表單后不會顯示成功/失敗消息

Question

我將此代碼在線放置在某個地方，除了成功和失敗消息外，它都可以工作。 當我提交表格時，它只是進入空白頁。 無論是否發送，如何顯示消息？ 請幫助，並提前致謝！ :)

HTML代碼：

<form class="form-horizontal" role="form" method="post" action="contact.php" style=" padding:30px;">
      <div class="form-group">
        <label for="name" class="col-sm-3 control-label">Name</label>
        <div class="col-sm-6">
          <input type="text" class="form-control" id="name" name="name" placeholder="First and Last Name">
          <?php echo $errName; ?>
        </div>
      </div>
      <div class="form-group">
        <label for="email" class="col-sm-3 control-label">Email</label>
        <div class="col-sm-6">
          <input type="email" class="form-control" id="email" name="email" placeholder="example@domain.com">
          <?php echo $errEmail; ?>
        </div>
      </div>
      <div class="form-group">
        <label for="message" class="col-sm-3 control-label">Message</label>
        <div class="col-sm-6">
          <textarea class="form-control" rows="4" name="message"></textarea><?php echo $errMessage; ?>

        </div>
      </div>

      <div class="form-group">
        <div class="col-sm-6 col-sm-offset-3">
          <input id="submit" name="submit" type="submit" value="Send" class="btn btn-primary">
        </div>
      </div>
      <div class="form-group">
        <div class="col-sm-6 col-sm-offset-3">
          <?php echo $result; ?>  
        </div>
      </div>
    </form> 

這是我的PHP代碼

    <?php
  if ($_POST["submit"]) {
    $name = $_POST['name'];
    $email = $_POST['email'];
    $message = $_POST['message'];
    $human = intval($_POST['human']);
    $from = 'Contact Form'; 
    $to = 'nikita_lim@rocketmail.com'; 
    $subject = 'New Message ';

    $success = mail($to, $subject, $message);

    $body ="From: $name\n E-Mail: $email\n Message:\n $message";
    // Check if name has been entered
    if (!$_POST['name']) {
      $errName = 'Please enter your name';
    }

    // Check if email has been entered and is valid
    if (!$_POST['email'] || !filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) {
      $errEmail = 'Please enter a valid email address';
    }

    //Check if message has been entered
    if (!$_POST['message']) {
      $errMessage = 'Please enter your message';
    }
// If there are no errors, send the email
if (!$errName && !$errEmail && !$errMessage) {
  if (mail ($to, $subject, $body, $from)) {
    $result='<div class="alert alert-success">Thank you for contacting us. We will be in touch with you very soon.
</div>';
  } else {
    $result='<div class="alert alert-danger">Sorry there was an error sending your message. Please try again later.</div>';
  }
}
  }
?>

Answer 1

試試這個PHP代碼

<?php
      if ($_POST["submit"]) {
        $name = $_POST['name'];
        $email = $_POST['email'];
        $message = $_POST['message'];
        //$human = intval($_POST['human']);
        $from = 'Contact Form'; 
        $to = 'nikita_lim@rocketmail.com'; 
        $subject = 'New Message ';

        //$success = mail($to, $subject, $message);

        $body ="From: $name\n E-Mail: $email\n Message:\n $message";
        // Check if name has been entered
        if (!$_POST['name']) {
          $errName = 'Please enter your name';
        }

        // Check if email has been entered and is valid
        if (!$_POST['email'] || !filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) {
          $errEmail = 'Please enter a valid email address';
        }

        //Check if message has been entered
        if (!$_POST['message']) {
          $errMessage = 'Please enter your message';
        }
    // If there are no errors, send the email
    if (!isset($errName) && !isset($errEmail) && !isset($errMessage)) {
      if (mail ($to, $subject, $body, $from)) {
        $result='<div class="alert alert-success">Thank you for contacting us. We will be in touch with you very soon.
    </div>';
      } else {
        $result='<div class="alert alert-danger">Sorry there was an error sending your message. Please try again later.</div>';
      }
    }
    else{
        $result='<div class="alert alert-danger">Please enter valid details.</div>';
        }
      }

    ?>

請在打印php變量之前使用isset或empty

Answer 2

$result='Sorry there was an error sending your message. Please try again later.';
echo "<script type='text/javascript'>alert('$result');</script>";