oracle SQL上的條件SUM

Question

我有以下方式的數據：

ITEM  LOCATION  UNIT RETAIL  QUANTITY 
100     KS         10          -10
200     KS         20           30

我想要正數量的總和（數量> 0）和負數量的總和（數量<0）。

如何根據條件獲得這些列總和？

Answer 1

您可以使用SUM(CASE ... ) ：

SELECT item, location,
   SUM(CASE WHEN quantity > 0 THEN quantity ELSE 0 END) AS positive_sum,
   SUM(CASE WHEN quantity < 0 THEN quantity ELSE 0 END) AS negative_sum
FROM your_table
GROUP BY item, location;

LiveDemo

Answer 2

您可以將GREATEST和LEAST與SUM函數結合使用：

SQL小提琴

Oracle 11g R2架構設置 ：

CREATE TABLE table_name ( ITEM, LOCATION, QUANTITY ) AS
          SELECT 100, 'KS', -10 FROM DUAL
UNION ALL SELECT 100, 'KS', -10 FROM DUAL
UNION ALL SELECT 100, 'KS', -20 FROM DUAL
UNION ALL SELECT 100, 'KS',  10 FROM DUAL
UNION ALL SELECT 100, 'KS',   5 FROM DUAL
UNION ALL SELECT 200, 'KS',  10 FROM DUAL
UNION ALL SELECT 200, 'KS',  20 FROM DUAL
UNION ALL SELECT 200, 'KS',   5 FROM DUAL

查詢1 ：

SELECT item,
       location,
       SUM( GREATEST( quantity, 0 ) ) AS positive_quantities,
       SUM( LEAST( quantity, 0 ) )    AS negative_quantities
FROM   table_name
GROUP BY item, location

結果 ：

| ITEM | LOCATION | POSITIVE_QUANTITIES | NEGATIVE_QUANTITIES |
|------|----------|---------------------|---------------------|
|  100 |       KS |                  15 |                 -40 |
|  200 |       KS |                  35 |                   0 |