一圈獲得20分后，如何停止游戲中的電腦玩家？

Question

我一直在嘗試用java制作一個叫做Pig的游戲，其中玩家擲出2個骰子。 玩家根據自己的擲骰數獲得積分，例如，如果玩家擲5和4，他現在有9分，但是如果玩家擲1，則不會獲得積分，並且控制權切換到計算機，並且如果玩家擲蛇眼（ 1和1），玩家失去了所有積分，控制權轉移到了計算機上。 我有游戲正常運行，但在其輪流獲得20分后，我需要停止計算機。 哪個玩家擊中100個首勝。

這是我的代碼：

//this program runs 4.4
import java.util.Scanner;


public class run {

    public static void main(String[] args) 
    {Scanner scan = new Scanner (System.in);
        dice thing = new dice();
        dice thing1 = new dice();
        boolean control=true;
        int x = 0,points=0,a,b,y=0,c,d,turn=0,save=0,no=0;
        while(x<100 && y<100)
        {
            while (control == true && x<100)
                {       
                    a=thing.roll();
                    b=thing1.roll();
                    if (a == 1 && b==1)
                    {
                        control=false;
                        System.out.println("your first die rolled a " + thing.getroll() + " second die rolled a " + thing1.getroll()+"computer now has control");
                        x=0;
                    }
                    else if(a == 1 || b==1)
                    {
                        control = false;
                        System.out.println("your first die rolled a " + thing.getroll() + " second die rolled a " + thing1.getroll() + " now you have " + x +" points "+"computer now has control");
                    }
                    else
                    {
                    x +=(a+b);
                    System.out.println("your first die rolled a " + thing.getroll() + " your second die rolled a  " + thing1.getroll() + " now you have " + x +" points" );
                System.out.println(" would you like to end your turn put in  1 for yes 0 for no");
                    points = scan.nextInt();
                    if(points==1)
                    {
                        control= false;
                    }
                    if (x>=100)
                        {
                            System.out.println("you win");
                        }
                    }
            }

            while (control==false && y<100)
                {   
                    c=thing.roll();
                    d=thing1.roll();

                    if (c == 1 && d==1)
                        {
                            control=true;
                            System.out.println("The computers first die rolled a " + thing.getroll() + " The computers second die rolled a " + thing1.getroll()+"you now have control");
                            turn = y;
                            y=0;
                        }
                    else if(c == 1 || d==1)
                        {
                            control = true;
                            System.out.println("The computers first die rolled a " + thing.getroll() + " The computers second die rolled a " + thing1.getroll()+ " now the computer has  " + y +" points "+"you now have control");
                            turn = y;
                        }
                    else
                        {
                        y +=(c+d);
                    System.out.println("The computers first die rolled a  " + thing.getroll() + " The computers second die rolled a " + thing1.getroll() + " now the computer has  " + y +" points" );
                        turn = y;
                        if (y>=100)
                            {
                                System.out.println("you lose");
                            }
                        }
            }
        }
    }
}

Answer 1

嘗試添加：

if (turn >= 20){
    control = true;
    turn = 0;
}

后：

while (control==false && y<100)
            {