[英]base64 code send to server by java script, ajax
我正在使用Html5,Java腳本,ajax和java。 我將圖像從桌面上傳到裁剪圖,裁剪圖在同一頁面中以自舉模式顯示后。 但是我沒有得到該圖像的URL,我得到了一些Base64代碼,當我發送該Base64代碼時,它無法正常工作。
我看到了這篇文章,但沒有從此鏈接獲得任何解決方案: https : //stackoverflow.com/
此代碼為靜態圖片,顯示為第一次。
我的代碼:
HTML:
<div class="img-container">
<img src="../assets/img/picture.jpg" alt="Picture">
</div>
<div class="modal fade docs-cropped" id="getCroppedCanvasModal" aria-hidden="true" aria-labelledby="getCroppedCanvasTitle" role="dialog" tabindex="-1">
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
<a class="btn btn-primary" id="download" download="cropped.png" href="javascript:void(0);">Upload</a>
</div>
</div>
Java腳本代碼:
(function () {
var $image = $('.img-container > img');
var $download = $('#download');
$('#getCroppedCanvasModal').modal().find('.modal-body').html(result);
if (!$download.hasClass('disabled')) {
$download.attr('href', result.toDataURL());
//console.log("*****************"+result.toDataURL());
var swapUrl = result.toDataURL();
console.log("*******" + swapUrl);
// document.getElementById('replaceMe').src = swapUrl;
$('#download').click(function () {
var b = result.toDataURL();
$.ajax({
url: "/sf/p/customizeText",
type: 'GET',
data: b,
success: function (response) {
console.log("999999999999999999999999999999999----------------" + b)
},
complete: function (response) {
},
error: function (response) {
}
});
});
}
}
我將result.toDataURL()分配給變量b。 但是它顯示了一些base64代碼。 我如何將此圖像發送到服務器。
嗨,您也可以檢查此解決方案
JavaScript代碼
var base64before = document.querySelector('img').src;
var base64 = base64before.replace(/^data:image\/(png|jpg);base64,/, "");
var httpPost = new XMLHttpRequest();
var path = "your url";
var data = JSON.stringify(base64);
httpPost.open("POST", path, false);
// Set the content type of the request to json since that's what's being sent
httpPost.setRequestHeader('Content-Type', 'application/json');
httpPost.send(data);
這是我的Java代碼。
public void saveImage(InputStream imageStream){
InputStream inStream = imageStream;
try {
String dataString = convertStreamToString(inStream);
byte[] imageBytes = javax.xml.bind.DatatypeConverter.parseBase64Binary(dataString);
BufferedImage image = ImageIO.read(new ByteArrayInputStream(imageBytes));
// write the image to a file
File outputfile = new File("/Users/paul/Desktop/testkey/myImage.png");
ImageIO.write(image, "png", outputfile);
}catch(Exception e) {
System.out.println(e.getStackTrace());
}
}
static String convertStreamToString(java.io.InputStream is) {
java.util.Scanner s = new java.util.Scanner(is).useDelimiter("\\A");
return s.hasNext() ? s.next() : "";
}
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