[英]AppGyver android show captured Image Issue
我需要在ApGyver類固醇應用程序中顯示捕獲的圖像。 我捕獲了圖像,然后嘗試在圖像中設置src。 但這給了我不允許本地資源的錯誤:
我正在以這種方式捕獲圖像:
var options = {
quality: 50,
targetWidth: 300,
targetHeight: 300,
destinationType: Camera.DestinationType.FILE_URI,
sourceType: Camera.PictureSourceType.CAMERA, // Camera.PictureSourceType.PHOTOLIBRARY
allowEdit: false,
encodingType: Camera.EncodingType.JPEG,
popoverOptions: CameraPopoverOptions,
saveToPhotoAlbum: true,
limit: 1
};
// capture callback
var captureSuccess = function(mediaFiles) {
var i, path, len;
console.log(mediaFiles);
for (i = 0, len = mediaFiles.length; i < len; i += 1) {
path = mediaFiles[i].localURL;
// do something interesting with the file
}
if (switched) {
$scope.post.media = []
}
$scope.post.media.length = 1;
$scope.post.fileUrl = path;
setActionType('image');
$scope.isBusy = false;
console.log('hello' + path);
};
// capture error callback
var captureError = function(error) {
navigator.notification.alert('Error code: ' + error.code, null, 'Capture Error');
};
// start image capture
navigator.device.capture.captureImage(captureSuccess, captureError, options);
嘗試使用此代碼來捕獲和上傳圖像。 並在index.html中鏈接cordova.js並添加相機插件。 仍然有任何問題告訴我。
function capturePhoto() {
navigator.camera.getPicture(uploadPhoto, onFail, {
quality: 50,
// allowEdit: true,
correctOrientation: true,
destinationType: Camera.DestinationType.FILE_URL,
// destinationType: Camera.DestinationType.DATA_URL
sourceType: Camera.PictureSourceType.CAMERA
});
}
function onFail(message) {
// alert('Failed because: ' + message);
}
function uploadPhoto(imageURI){
console.log(imageURI);
var options = new FileUploadOptions();
options.fileKey="file";
options.fileName=imageURI.substr(imageURI.lastIndexOf('/')+1);
options.mimeType="image/jpeg";
var ft = new FileTransfer();
ft.upload(imageURI, encodeURI("http://XYZ/uploadimg?user_id="+UserId+""), winGallary, fail, options);
console.log(ft.upload);
}
function winGallary(rGallary) {
console.log("Code = " + rGallary.responseCode);
console.log("Response = " + rGallary.response);
console.log("Sent = " + rGallary.bytesSent);
}
function fail(error) {
console.log("upload error source " + error.source);
console.log("upload error target " + error.target);
}
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