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[英]Reading from jar file in local filesystem using hadoop FileSystem
[英]Apache httpclient GET file from local filesystem?
我總是認為這應該是可能的:
val client = HttpClients.createDefault()
val httpGet = new HttpGet("file:///Users/user01/testfile")
client.execute(httpGet)
拋出:
client: org.apache.http.impl.client.CloseableHttpClient = org.apache.http.impl.client.InternalHttpClient@4ba3987b
httpGet: org.apache.http.client.methods.HttpGet = GET file:///Users/user01/testfile HTTP/1.1
org.apache.http.client.ClientProtocolException: URI does not specify a valid host name: file:///Users/user01/testfile
at org.apache.http.impl.client.CloseableHttpClient.determineTarget(test_ws.sc0.tmp:90)
at org.apache.http.impl.client.CloseableHttpClient.execute(test_ws.sc0.tmp:78)
at org.apache.http.impl.client.CloseableHttpClient.execute(test_ws.sc0.tmp:103)
at #worksheet#.#worksheet#(test_ws.sc0.tmp:6)
當我創建一個HttpGet
實例時, HttpGet
。
有誰知道如何做到這一點?
令人驚訝的是,HttpClient是一個客戶端HTTP傳輸庫。 它不支持任何其他傳輸協議。 甚至不是本地文件系統。 你可能想要的是Apache Commons VFS或類似的東西。
HttpClient實際上只適用於HTTP,但您可以使用普通Java實現相同的功能:
try (BufferedInputStream in = new BufferedInputStream(new URL("file:///tmp/test.in").openStream());
FileOutputStream fileOutputStream = new FileOutputStream(new File("/tmp/test.out"))){
byte dataBuffer[] = new byte[1024];
int bytesRead;
while ((bytesRead = in.read(dataBuffer, 0, 1024)) != -1) {
fileOutputStream.write(dataBuffer, 0, bytesRead);
}
} catch(IOException e){
e.printStackTrace();
}
那么使用內置的java.net.URL
類呢? 它處理http和文件協議。
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