表單提交有兩個動作

Question

我正在嘗試創建一個頁面，表單提交將在其中執行兩個操作。 在 index.php 中，第一個動作是使用 ajax 發送要保存在數據庫中的數據。 第二個動作是它將頁面更改為 index1.php。 我創建的代碼成功地將數據保存到數據庫中，但它不會更改為 index1.php。 我的代碼有什么問題？

索引.php

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>

<script>
$(document).ready(function(){
$("#submit").click(function(){
var radio1 = $("input[name=group1]:checked").val();
var radio2 = $("input[name=group2]:checked").val();
var radio3 = $("input[name=group3]:checked").val();
var radio4 = $("input[name=group4]:checked").val();
// Returns successful data submission message when the entered information is stored in database.
var dataString = '&submit1='+ radio1 + '&submit2='+ radio2 + '&submit3='+ radio3 + '&submit4='+ radio4;

if(radio1==''||radio2==''||radio3==''||radio4=='')
{
alert("Please Fill All Fields");
}
else
{
// AJAX Code To Submit Form.
$.ajax({
type: "POST",
url: "ajaxsubmit.php",
data: dataString,
cache: false,
success: function(result){
alert(result);
}
});
}
return false;
});
});
</script>

<form action="index1.php" method="post">
                <hr>
                        <label>Alignment: </label>
                        <input type="radio" name="group1" value="5"> 5
                        <input type="radio" name="group1" value="4"> 4
                        <input type="radio" name="group1" value="3"> 3
                        <input type="radio" name="group1" value="2"> 2
                        <input type="radio" name="group1" value="1"> 1
                        <hr>
                        <label>Blend: </label>
                        <input type="radio" name="group2" value="5"> 5
                        <input type="radio" name="group2" value="4"> 4
                        <input type="radio" name="group2" value="3"> 3
                        <input type="radio" name="group2" value="2"> 2
                        <input type="radio" name="group2" value="1"> 1
                        <hr>
                        <label>Warp: </label>
                        <input type="radio" name="group3" value="5"> 5
                        <input type="radio" name="group3" value="4"> 4
                        <input type="radio" name="group3" value="3"> 3
                        <input type="radio" name="group3" value="2"> 2
                        <input type="radio" name="group3" value="1"> 1
                        <hr>
                        <label>Overall: </label>
                        <input type="radio" name="group4" value="5"> 5
                        <input type="radio" name="group4" value="4"> 4
                        <input type="radio" name="group4" value="3"> 3
                        <input type="radio" name="group4" value="2"> 2
                        <input type="radio" name="group4" value="1"> 1
                <hr>
                <input type="submit" id="submit" name="submit" value="Submit" class="button">
 </form>

Answer 1

ajax成功后需要更改位置：

$.ajax({
    type: "POST",
    url: "ajaxsubmit.php",
    data: dataString,
    cache: false,
    success: function(result){
        alert(result);
        window.location = '/index1.php';
    }
});