[英]How to order a dictionary within a list by alphabetical order and highest number
我有一個基本的代碼如下:
dict1 = [{"Name":"Ron","one":3,"two":6,"three":10}
,{"Name":"Mac","one":5,"two":8,"three":0}
,{"Name":"DUDE","one":16,"two":9,"three":2}]
print(dict1)
import operator
dict1.sort(key=operator.itemgetter("Name"))
print("\nStudents Alphabetised\n")
for pupil in dict1:
print ("StudentName",pupil["Name"],pupil["one"],pupil["two"],pupil["three"])
我已經對其進行了排序,以便可以按字母順序打印出人們的姓名,但是,我現在需要工作的代碼,以便可以按字母順序打印出姓名,但是也只能打印出最高分。
您的樂譜存儲在三個單獨的鍵中; 使用max()
函數選擇最高的一個:
for pupil in dict1:
highest = max(pupil["one"], pupil["two"], pupil["three"])
print("StudentName", pupil["Name"], highest)
通過將所有樂譜存儲在列表中而不是三個單獨的鍵中,可以使您的生活更輕松:
dict1 = [
{"Name": "Ron", 'scores': [3, 6, 10]},
{"Name": "Mac", 'scores': [5, 8, 0]},
{"Name": "DUDE", 'scores': [16, 9, 2]},
]
然后,您仍然可以使用pupil['scores'][index]
(其中index
是一個整數,從0、1或2中選擇)來解決單個分數,但是最高分數就和max(pupil['scores'])
。
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