如何在Python中拆分此字符串？

Question

我有一個變量string 。

string = '''Layer:defaultRenderLayer
Line 1 text goes here
Line 2 text goes here
Line 3 text goes here
Layer:diffuse
Line 1 text goes here
Line 2 text goes here
Line 3 text goes here
Line 4 text goes here
Line 5 text goes here
Layer:outline
Line 1 text goes here
Line 2 text goes here'''

我正試圖在文本Layer之前拆分字符串，如下所示。

string_list = [
    'Layer:defaultRenderLayer\nLine 1 text goes here\nLine 2 text goes here\nLine 3 text goes here',
    'Layer:diffuse\nLine 1 text goes here\nLine 2 text goes here\nLine 3 text goes here\nLine 4 text goes here\nLine 5 text goes here',
    'Layer:outline\nLine 1 text goes here\nLine 2 text goes here'
]

Answer 1

import re
print re.split(r"\n(?=Layer)",x)

您可以使用lookahead與re這里來達到相同。

輸出：

['Layer:defaultRenderLayer\nLine 1 text goes here\nLine 2 text goes here\nLine 3 text goes here', 
 'Layer:diffuse\nLine 1 text goes here\nLine 2 text goes here\nLine 3 text goes here\nLine 4 text goes here\nLine 5 text goes here', 
 'Layer:outline\nLine 1 text goes here\nLine 2 text goes here']

或者您也可以使用re.findall 。

print re.findall(r"\bLayer\b[\s\S]*?(?=\nLayer\b|$)",x

見演示

Answer 2

你需要使用re.split

re.split(r'\s+(?=Layer:)', string)

這將拆分一個或多個空格字符，這些空格字符就在字符串Layer:之前。 並注意\\s將匹配任何類型的空格字符，即垂直（ 換行符，carrage返回 ）以及水平空格字符（ 空格，制表符 ）。

例：

>>> import re
>>> string = '''Layer:defaultRenderLayer
Line 1 text goes here
Line 2 text goes here
Line 3 text goes here
Layer:diffuse
Line 1 text goes here
Line 2 text goes here
Line 3 text goes here
Line 4 text goes here
Line 5 text goes here
Layer:outline
Line 1 text goes here
Line 2 text goes here'''
>>> re.split(r'\s+(?=Layer:)', string)
['Layer:defaultRenderLayer\nLine 1 text goes here\nLine 2 text goes here\nLine 3 text goes here', 'Layer:diffuse\nLine 1 text goes here\nLine 2 text goes here\nLine 3 text goes here\nLine 4 text goes here\nLine 5 text goes here', 'Layer:outline\nLine 1 text goes here\nLine 2 text goes here']