如何獲取PHP中最后插入的ID

Question

在這里，我嘗試從MySQL數據庫中獲取插入的ID，該表具有product_id。 插入后，我想獲取最新插入的product_id並將其存儲在數組['newid'][]

插入查詢進行得很好，但是我無法將product_id放入數組。 當我打印數組時，我得到的是NULL值。

 $link = mysqli_connect(db_host,db_user,db_password,db_name);    
    if (condition) {
    $sqlin = "INSERT INTO product_list (product_name, product_category, product_price,product_description,product_sharing_basis,product_co_owners,walden_product_price,product_referrence_URL,product_proposed_user_id,product_image_url,product_refurbish_factor,product_insurance_factor,product_life,product_size_category,product_publish_status) VALUES ('$product_name', '$product_category', '$product_price', '$product_description', '$share_basis', '$co_owners', '$walden_product_price', '$pro_url', '$proposed_by','files/uploaded_images/".$_FILES['file']['name']."', '$refurbishment_factor', '$insurance_factor', '$product_life', '$size_category','$approve')";          
    } else {
    $sqlin = "INSERT INTO product_list (product_name, product_category, product_price,product_description,product_sharing_basis,product_co_owners,walden_product_price,product_referrence_URL,product_proposed_user_id,product_image_url,product_refurbish_factor,product_insurance_factor,product_life,product_size_category) VALUES ('$product_name', '$product_category', '$product_price', '$product_description', '$share_basis', '$co_owners', '$walden_product_price', '$pro_url', '$proposed_by','files/uploaded_images/".$_FILES['file']['name']."', '$refurbishment_factor', '$insurance_factor', '$product_life', '$size_category')";
    }
    if(mysqli_query($link, $sqlin)){    
        $newisid = mysqli_insert_id($link);
        $_SESSION['newid'][] = $newisid;

我該如何解決？

Answer 1

php.net：$ mysqli-> insert_id

    $mysqli = new mysqli("localhost", "my_user", "my_password", "world");

/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

$mysqli->query("CREATE TABLE myCity LIKE City");

$query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";
$mysqli->query($query);

printf ("New Record has id %d.\n", $mysqli->insert_id);

Answer 2

嘗試使用mysql_insert_id()獲取先前插入的ID。

if (mysqli_query($conn, $sql)) {
    $last_id = mysqli_insert_id($conn);//previously insert id here.

} else {
    //error
}

看到這個和這個

編輯

您也可以為此使用LAST_INSERT_ID() 。 查看官方mysql 文檔

Answer 3

嘗試這個：

$link = mysqli_connect(db_host,db_user,db_password,db_name);

if (condition) {
    $sqlin = "INSERT INTO product_list (product_name, product_category, product_price,product_description,product_sharing_basis,product_co_owners,walden_product_price,product_referrence_URL,product_proposed_user_id,product_image_url,product_refurbish_factor,product_insurance_factor,product_life,product_size_category,product_publish_status) VALUES ('$product_name', '$product_category', '$product_price', '$product_description', '$share_basis', '$co_owners', '$walden_product_price', '$pro_url', '$proposed_by','files/uploaded_images/".$_FILES['file']['name']."', '$refurbishment_factor', '$insurance_factor', '$product_life', '$size_category','$approve')";          
} else {
    $sqlin = "INSERT INTO product_list (product_name, product_category, product_price,product_description,product_sharing_basis,product_co_owners,walden_product_price,product_referrence_URL,product_proposed_user_id,product_image_url,product_refurbish_factor,product_insurance_factor,product_life,product_size_category) VALUES ('$product_name', '$product_category', '$product_price', '$product_description', '$share_basis', '$co_owners', '$walden_product_price', '$pro_url', '$proposed_by','files/uploaded_images/".$_FILES['file']['name']."', '$refurbishment_factor', '$insurance_factor', '$product_life', '$size_category')";
}


if($link->query($sqlin)){
    $newisid = $link->insert_id;
    $_SESSION['newid'][] = $newisid;
}

參考： http : //php.net/manual/en/mysqli.insert-id.php