對待SpriteKit Swift中的每個節點

Question

每次單擊屏幕時，我都會新建一個圓形的SKShapeNode。

我試圖做下一件事：每當新的SKShapeNode進入地下時（地面y是屏幕的一半），他就會變成綠色。 所以我嘗試了這個：

override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) {
newestBall = SKShapeNode(circleOfRadius: 10)
        newestBall.physicsBody = SKPhysicsBody(circleOfRadius: newestBall.frame.height / 2)
        newestBall.position = CGPoint(x: CGRectGetMidX(self.frame) ,y: self.frame.size.height - newBall.frame.height)
        newestBall.fillColor = SKColor.blueColor()
        newestBall.strokeColor = SKColor.blackColor()
        newestBall.glowWidth = 1.0
        newestBall.zPosition = 9
        newestBall.physicsBody?.dynamic = true
        newestBall.physicsBody?.allowsRotation = false
        newestBall.physicsBody?.friction = 0
        newestBall.physicsBody?.restitution = 1
        newestBall.physicsBody?.linearDamping = 0
        newestBall.physicsBody?.angularDamping = 0
        newestBall.physicsBody?.categoryBitMask = ballsGroup
}
override func update(currentTime: CFTimeInterval) {
if newestBall.position.y < ground.position.y {
            newestBall.fillColor = SKColor.greenColor()
        }
}

而且有效！ 但是，每當我單擊兩次並創建2個球（並且第一個球仍未進入地下）時，只有最后一個球變成綠色，因為他是newestBall 。

如果他掉入地下，我想使每個球變成綠色。

Answer 1

給您的newestBall一個名字：

newestBall.name = "Ball"

然后檢查所有名稱為“ Ball”的節點，並更改顏色ir的要求

self.enumerateChildNodesWithName("Ball", usingBlock: {
        (node: SKNode!, stop: UnsafeMutablePointer <ObjCBool>) -> Void in
        let shapeNode = node as! SKShapeNode
        if shapeNode < self.ground.position.y {

            shapeNode = SKColor.greenColor()
        }
    })

您可以將其添加到update() 。 self是parentNode或您的newBall和Ground節點。