[英]How to print all the result of each loop one time in python
下面的程序要求用戶輸入“測試用例數”,然后輸入數字以對其進行操作。 最后,我想打印循環中每個操作的結果。
這是代碼:
test_case = int(raw_input()) # User enter here the number of test case
for x in range(test_case):
n = int(raw_input())
while n ! = 1: # this is the operation
print n,1, #
if n % 2 == 0:
n = n//2
else:
n = n*3+1
如果我在測試用例中輸入“2”並且在每種情況下輸入2個數字,則輸出如下。 例如22和64,它將是這樣的:
2
22 # the first number of the test case
22 1 11 1 34 1 17 1 52 1 26 1 13 1 40 1 20 1 10 1 5 1 16 1 8 1 4 1 2 1 # it prints the result immediately
64 # second test case
64 1 32 1 16 1 8 1 4 1 2 1 # it prints it immediately as the first
以下是預期的輸出:
2
22
64
用戶輸入測試用例后的輸出和測試用例的所有數字是:
22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1
64 32 16 8 4 2 1
我該如何解決這個問題?
注意:我嘗試將結果保存在列表中並打印,但它會將所有結果打印在一行中。
#Gets the number of test cases from the user
num_ops = int(raw_input("Enter number of test cases: "))
#Initilze the list that the test cases will be stored in
test_cases = list()
#Append the test cases to the test_cases list
for x in range(num_ops):
test_cases.append(int(raw_input("Enter test case")))
#Preform the operation on each of the test cases
for n in test_cases:
results = [str(n)]
while n != 1: # this is the operation
if n % 2 == 0:
n = n//2
else:
n = n*3+1
results.append(str(n))
print ' '.join(results)
完全按照您的描述輸出,但輸入文本提示更加清晰。
enter number of test cases: 2
enter test case: 22
enter test case: 64
22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1
64 32 16 8 4 2 1
你的縮進有一些問題,但我假設這只是在問題中,而不是在真正的程序中。
因此,您希望首先輸入所有測試用例,執行它們,最后顯示結果。 要獲得測試用例,您可以執行類似的操作
num_test_cases = int(input())
test_cases = [0] * num_test_cases
for x in range(num_test_cases):
test_cases.append(input())
之后,您可以使用相同的代碼執行算法,但將結果保存在列表中(如您所述)
...
results = {}
for x in test_cases:
n = int(x)
results[x] = []
while n != 1:
results[x].append(n)
...
最后你可以打印出你的結果
for result in results
print(results)
如果要在同一行上打印序列,可以執行以下操作。
test_case=int(raw_input()) # User enter here the number of test case
for x in range(test_case):
n=int(raw_input())
results = []
while n != 1: # this is the operation
results.append(n)
if n % 2 == 0:
n=n//2
else:
n=n*3+1
print(' '.join(results)) # concatenates the whole sequence and puts a space between each number
我認為這非常接近你想要的。
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