比較兩個具有相同列名但具有匯總的表

Question

我正在努力實現這一目標。

TBL 1  
PK   AK   TOT1   TOT2  
1    1    100    100  
2    2    200    200


TBL 2  
PK   AK   TOT1   TOT2  
1    1     50     50  
2    1     50     50  
3    2     100    100  
4    2     50     50

我的主表是TBL1 ，並且首先與AK連接，我需要對所有TBL2的AK求和，然后將其與TBL1進行比較。

IE瀏覽器
TBL1.AK(1).TOT1 = 100 == TBL2.AK(1).sum(TOT1) = 100是正確的
TBL1.AK(2).TOT2 = 200 == TBL2.AK(2).sum(TOT2) = 150這是錯誤的。

我需要返回不相等的列

Return TBL  
PK   AK   TBL1.TOT1   TBL2.TOT2  
2    2     200         150 

--Assumed that TBL2 is already totaled.

我已經嘗試過了：

Select AK, SUM(t1.TOT1), SUM(t2.TOT2)  
FROM TBL1 t1  
JOIN TBL2 t2  
ON t1.AK = t2.AK  
GROUP BY t1.AK  
WHERE t1.TOT1 IS NOT t2.TOT2 ....

它返回t1.AK並與t2.TOT1和t2.TOT2之和，但不t1.TOT1和t1.TOT2 。

更新：
到目前為止我已經嘗試過了
SELECT t1.AK, sum(t2.TOT1) FROM TBL1 t1 JOIN TBL t2 ON t1.AK = t2.AK GROUP BY t1.AK HAVING t1.TOT1 <> sum(t2.TOT1)

它返回我“00979。00000-“不是GROUP BY表達式””

Answer 1

在進行加入之前匯總：

Select t1.AK, t1.TOT1, t2.TOT2
FROM TBL1 t1 LEFT JOIN
     (SELECT ak, SUM(TOT2) as TOT2
      FROM TBL2 t2  
      GROUP BY ak
     ) t2
     ON t1.AK = t2.AK
WHERE t1.TOT1 <> t2.TOT2 OR t2.TOT2 IS NULL;

編輯：添加了t2。 在最后一行刪除列的歧義

Answer 2

 WITH table1 AS (SELECT 1 AS ak, 100 AS tot1, 100 AS tot2 FROM dual UNION ALL
                   SELECT 2 AS ak, 200 AS tot1, 200 AS tot2 FROM dual  ),
         table2 AS (SELECT 1 AS ak, 50 AS tot1, 50 AS tot2 FROM dual UNION ALL
                  SELECT 1 AS ak, 50 AS tot1, 50 AS tot2 FROM dual UNION ALL
                  SELECT 2 AS ak, 100 AS tot1, 100 AS tot2 FROM dual UNION ALL
                  SELECT 2 AS ak, 50 AS tot1, 50 AS tot2 FROM dual )


SELECT table1.ak, table1.tot1, z.tot1 
FROM table1 JOIN
(SELECT table2.ak ak, sum(table2.tot1) tot1, sum(table2.tot2) tot2
FROM table2
GROUP By table2.ak) z ON table1.ak = z.ak
WHERE   table1.tot1 <> z.tot1 
 AND    table1.tot2 <> z.tot2;