[英]Semaphore crashes android app
作為初次嘗試在高中時為Comp Sci制作快速便捷的android應用程序的人,我一直在努力將功能強大的冒險風格游戲移植到android 5.1.1。 您在兩個按鈕之間進行選擇,穿過古老的令人毛骨悚然的房子,您的選擇會影響結果。 我解決的方法是使用帶有switch語句的do循環,使用信號量等待選擇。 使用信號量似乎使我的應用程序崩潰:Logcat沒有顯示任何錯誤,但是當我甚至在使用switch功能之前在開始時放置調試選項時,嘗試獲取信號量時應用程序便崩潰了。 注釋掉信號量可以解決問題。
tl; dr在Android上處理兩鍵選擇的更合適的方法是什么?
這是代碼:
冒險游戲的主要部分
public static Button btnYes, btnNo;
public static TextView textField;
public static Semaphore semaphore = new Semaphore(0);
public static String btnUsed = "";
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_adventure);
btnYes = (Button) findViewById(R.id.buttonYes);
btnNo = (Button) findViewById(R.id.buttonNo);
textField = (TextView) findViewById(R.id.textFieldText);
textField.setText("Debug Screen! Begin?");
btnYes.setText("Yes");
btnNo.setText("No");
try {
semaphore.acquire();
Switch();
} catch (InterruptedException e) {
}
}
public void btnYesClicked(View v) {
btnUsed = Prompts.yes;
semaphore.release();
}
public void btnNoClicked(View v) {
btnUsed = Prompts.no;
semaphore.release();
}
public static void Switch() throws InterruptedException {
boolean isRunning = true;
String place = Prompts.doorway;
String choice = "";
do {
switch (place) {
case Prompts.doorway:
semaphore.drainPermits();
textField.setText(Prompts.doorwayPrompt);
btnYes.setText(Prompts.kitchen);
btnNo.setText(Prompts.upstairs);
semaphore.acquire();
choice = btnUsed;
if (choice.equals(Prompts.yes) || choice.equals(Prompts.no)) {
if (choice.equals(Prompts.yes)) {
place = Prompts.kitchen;
} else {
place = Prompts.upstairs;
}
} else {
place = "default";
}
break;
case Prompts.kitchen:
semaphore.drainPermits();
textField.setText(Prompts.kitchenPrompt);
btnYes.setText(Prompts.fridge);
btnNo.setText(Prompts.cabinet);
semaphore.acquire();
choice = btnUsed;
if (choice.equals(Prompts.yes) || choice.equals(Prompts.no)) {
if (choice.equals(Prompts.yes)) {
place = Prompts.fridge;
} else {
place = Prompts.cabinet;
}
} else {
place = "default";
}
break;
case Prompts.upstairs:
semaphore.drainPermits();
textField.setText(Prompts.upstairsPrompt);
btnYes.setText(Prompts.bedroom);
btnNo.setText(Prompts.bathroom);
semaphore.acquire();
choice = btnUsed;
if (choice.equals(Prompts.yes) || choice.equals(Prompts.no)) {
if (choice.equals(Prompts.yes)) {
place = Prompts.bedroom;
} else {
place = Prompts.bathroom;
}
} else {
place = "default";
}
break;
case Prompts.fridge:
semaphore.drainPermits();
textField.setText(Prompts.fridgePrompt);
btnYes.setText(Prompts.yes);
btnNo.setText(Prompts.no);
semaphore.acquire();
choice = btnUsed;
if (choice.equals(Prompts.yes) || choice.equals(Prompts.no)) {
if (choice.equals(Prompts.yes)) {
textField.setText(Prompts.fridgeYes);
place = "done";
} else {
textField.setText(Prompts.fridgeNo);
place = "done";
}
}
break;
case Prompts.cabinet:
semaphore.drainPermits();
textField.setText(Prompts.cabinetPrompt);
btnYes.setText(Prompts.yes);
btnNo.setText(Prompts.no);
semaphore.acquire();
choice = btnUsed;
if (choice.equals(Prompts.yes) || choice.equals(Prompts.no)) {
if (choice.equals(Prompts.yes)) {
textField.setText(Prompts.cabinetYes);
place = "done";
} else {
textField.setText(Prompts.cabinetNo);
place = "done";
}
}
break;
case Prompts.bedroom:
semaphore.drainPermits();
textField.setText(Prompts.bedroomPrompt);
btnYes.setText(Prompts.yes);
btnNo.setText(Prompts.no);
semaphore.acquire();
choice = btnUsed;
if (choice.equals(Prompts.yes) || choice.equals(Prompts.no)) {
if (choice.equals(Prompts.yes)) {
textField.setText(Prompts.bedroomYes);
place = "done";
} else {
textField.setText(Prompts.bedroomNo);
place = "done";
}
}
break;
case Prompts.bathroom:
semaphore.drainPermits();
textField.setText(Prompts.bathroomPrompt);
btnYes.setText(Prompts.yes);
btnNo.setText(Prompts.no);
semaphore.acquire();
choice = btnUsed;
if (choice.equals(Prompts.yes) || choice.equals(Prompts.no)) {
if (choice.equals(Prompts.yes)) {
textField.setText(Prompts.bathroomYes);
place = "done";
} else {
textField.setText(Prompts.bathroomNo);
place = "done";
}
}
break;
case "done":
semaphore.drainPermits();
btnYes.setText("Again");
btnNo.setText("Finish");
semaphore.acquire();
choice = btnUsed;
if (choice.equals(Prompts.yes) || choice.equals(Prompts.no)) {
if (choice.equals(Prompts.yes)) {
place = Prompts.doorway;
} else {
isRunning = false;
}
}
default:
textField.setText("Not a valid answer!");
break;
}
} while (isRunning);
}
活動XML
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
android:paddingBottom="@dimen/activity_vertical_margin"
tools:context=".Adventure">
<TextView android:text="@string/app_name"
android:layout_width="wrap_content"
android:id="@+id/textFieldText"
android:layout_height="wrap_content"
android:layout_marginTop="73dp"
android:layout_alignParentTop="true"
android:layout_centerHorizontal="true" />
<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/yes"
android:id="@+id/buttonYes"
android:layout_alignTop="@+id/buttonNo"
android:onClick="btnYesClicked"
android:layout_alignParentStart="true" />
<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/no"
android:id="@+id/buttonNo"
android:layout_centerVertical="true"
android:onClick="btnNoClicked"
android:layout_alignParentEnd="true" />
</RelativeLayout>
如評論中所述,您正在阻止UI。 一種更好的處理方法是將String place
存儲在字段變量中(例如您所使用的按鈕)。 更改您的Switch()
方法以接受選擇參數Switch(String choice)
並消除do / while,然后更改btnYesClicked
和btnNoClicked
來調用Switch方法並傳遞正確的按鈕。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.