[英]How to execute sh command set in shell variable?
我有這個linux命令:
candump -l -e -x -s 0 -n 10任意,0〜0,#FFFFFFFF 2> / dev / null> /tmp/can.log&
當我直接在shell中運行它時,它可以正常工作。
我想使用以下方法將其添加到腳本中:
#!/bin/sh
# I tried this 2 syntax
# MYVAR="candump -l -e -x -s 0 -n 10 any,0~0,#FFFFFFFF 2> /dev/null > /tmp/can.log &"
MYVAR='candump -l -e -x -s 0 -n 10 any,0~0,#FFFFFFFF 2> /dev/null > /tmp/can.log &'
$MYVAR
當我執行腳本時,出現以下錯誤:
SIOCGIFINDEX:沒有這樣的設備
我已經測試了這些腳本,並且可以正常工作:
#!/bin/sh
MYVAR='ls -l'
$MYVAR
結果:
total 8
drwxr-xr-x 2 root root 0 Nov 5 2015 bin
drwxr-xr-x 2 root root 0 Oct 22 2015 boot
drwxr-xr-x 5 root root 13460 Jan 1 00:00 dev
drwxr-xr-x 8 root root 0 Nov 5 2015 etc
drwxr-xr-x 3 root root 0 Nov 5 2015 home
-rwsr-xr-x 1 root root 258 Nov 5 2015 init
drwxr-xr-x 3 root root 0 Nov 5 2015 lib
drwxr-xr-x 3 root root 0 Nov 5 2015 media
drwxr-xr-x 3 root root 0 Nov 5 2015 mnt
dr-xr-xr-x 67 root root 0 Jan 1 00:00 proc
drwx------ 2 root root 0 Oct 22 2015 root
drwxr-xr-x 4 root root 0 Jan 1 00:00 run
drwxr-xr-x 2 root root 0 Nov 5 2015 sbin
dr-xr-xr-x 14 root root 0 Jan 1 00:00 sys
-rwxr-xr-x 1 root root 33 Jan 1 00:04 test
drwxrwxrwt 2 root root 0 Jan 1 00:00 tmp
drwxr-xr-x 9 root root 0 Oct 22 2015 usr
drwxr-xr-x 7 root root 0 Oct 22 2015 var
我看不到錯誤,您能解釋一下錯誤嗎?
#!/bin/sh
myfunc() {
candump -l -e -x -s 0 -n 10 any,0~0,#FFFFFFFF 2>/dev/null >/tmp/can.log &
}
# call it
myfunc
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