[英]MySQL, group by two different columns
我的表看起來像:
╔═════╦═════════════════════╦═════════════════════╦═════════════╗
║ id ║ begin ║ end ║ employeesId ║
╠═════╬═════════════════════╬═════════════════════╬═════════════╣
║ 4 ║ 2015-11-11 00:00:00 ║ 2015-11-11 09:00:00 ║ 8 ║
║ 80 ║ 2015-11-11 09:00:00 ║ 2015-11-11 12:00:00 ║ 8 ║
║ 49 ║ 2015-11-11 00:00:00 ║ 2015-11-11 08:00:00 ║ 61 ║
║ 32 ║ 2015-11-11 08:00:00 ║ 2015-11-12 06:00:00 ║ 61 ║
║ 42 ║ 2015-11-12 07:00:00 ║ 2015-11-12 13:00:00 ║ 61 ║
║ 17 ║ 2015-11-11 00:00:00 ║ 2015-11-11 08:00:00 ║ 22 ║
║ 42 ║ 2015-11-11 09:00:00 ║ 2015-11-11 12:00:00 ║ 22 ║
╚═════╩═════════════════════╩═════════════════════╩═════════════╝
我想合並其中employeesId
列相等的行,並且一行的begin
時間等於另一行的end
時間。 像這樣:
╔═════════════════════╦═════════════════════╦═════════════╗
║ begin ║ end ║ employeesId ║
╠═════════════════════╬═════════════════════╬═════════════╣
║ 2015-11-11 00:00:00 ║ 2015-11-11 12:00:00 ║ 8 ║
║ 2015-11-11 00:00:00 ║ 2015-11-12 06:00:00 ║ 61 ║
║ 2015-11-12 07:00:00 ║ 2015-11-12 13:00:00 ║ 61 ║
║ 2015-11-11 00:00:00 ║ 2015-11-11 08:00:00 ║ 22 ║
║ 2015-11-11 09:00:00 ║ 2015-11-11 12:00:00 ║ 22 ║
╚═════════════════════╩═════════════════════╩═════════════╝
編輯:
我需要合並連續的日期時間,在這個例子中,您可以看到employeeId = 8的結束時間'2015-11-11 12:00:00'替換了第一行的結束時間'2015-11-11 09:00:00'因為第二行的開頭等於第一行的結尾。
嘗試加入
SELECT a.`begin_date`, IF(b.`end_date` IS NOT NULL, b.`end_date`, a.`end_date`), a.`employer_id`
FROM `mytable` a
LEFT JOIN `mytable` b ON a.`employer_id` = b.`employer_id` AND a.`end_date` = b.`begin_date`
LEFT JOIN `mytable` c ON a.`employer_id` = c.`employer_id` AND a.`begin_date` = c.`end_date`
WHERE c.`id` IS NULL
但是你應該重建你的架構。
如果想要更早和更晚的時間MIN(),MAX()
可以使用MIN(),MAX()
。
SELECT MIN(begin),MAX(end),employeesId
FROM table_name
GROUP BY employeesId
希望這可以幫助
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