C ++：如何使代碼自動輸入隨機數？

Question

我正在研究這個簡單的代碼，總之，它應該一直要求您輸入的數字與您嘗試輸入的次數不同，因此，它將開始要求您不要輸入0，只要您輸入不要輸入0，它會重申並要求您不要輸入1。

但是，我想修改該程序，以使其能夠嘗試隨機輸入來運行，只是想知道在獲得正確的數字之前它將運行多長時間。

在卡住之前，這是我想到的：

#include <iostream>

//i was told the following libraries give you random numbers
#include <time.h>
#include <cstdlib> 
#include <conio.h>

using namespace std;

int main() {
    int numberAttempts = -2;
    int numberEntered = !(numberAttempts);

    int xRan;    // I was told this little bit should get you random numbers
    srand(time(0));

    xRan = rand() % 100 + 1; //arbitrary randomization rule

    while (!((numberAttempts+1)==numberEntered)){

        int counter = numberAttempts + 2;

        cout << "Please enter any number but " << counter
             << ".\n>>";

        numberEntered ==  //here is where i'd like to have a random input. 

        cout << "Number Entered: " << numberEntered
             << endl;
        numberAttempts++;

        }
    cout << "\n\nWhy the did you do that?\n\n\n\n";

    system("pause");
    return 0;
}

設置號numberEntered = xRan; 使它與在第一次迭代中將numberEntered設置為0相同：它會響應但立即關閉。

我堅信這只是重新分配numberEntered的問題，但我不知道如何。

預先感謝您的關注。

Answer 1

這很簡單，將while（）循環中的rand() % 100 + 1從xRan移到numberEntered 。 實際上，您可以完全xRan變量。 您的代碼已實現，如下所示。 但是請注意，因為如果嘗試次數超過100而未與numberAttempts匹配，則隨機函數將僅返回1-100之間的值，因此循環將永遠運行並最終崩潰。 為了解決這個問題，我在while循環中放入了另一個必要條件!((numberAttempts+1)==numberEntered) && (numberAttempts < 100)

#include <iostream>

//i was told the following libraries give you random numbers
#include <time.h>
#include <cstdlib> 
#include <conio.h>

using namespace std;

int main() {
    int numberAttempts = -2;
    int numberEntered = !(numberAttempts);

    srand(time(0));

    while (!((numberAttempts+1)==numberEntered) && (numberAttempts < 100)){

        int counter = numberAttempts + 2;

        cout << "Please enter any number but " << counter
             << ".\n>>";

        numberEntered = rand() % 100 + 1;

        cout << "Number Entered: " << numberEntered
             << endl;
        numberAttempts++;

        }
    cout << "\n\nWhy the did you do that?\n\n\n\n";

    system("pause");
    return 0;
}

注意：此代碼並非每次都有效。 以下是工作迭代