在Rails中創建嵌套資源時沒有路由匹配

Question

我正在嘗試為我的項目中的特定學校創建一個新老師，我收到了這個錯誤：

沒有路線匹配[POST]“/ schools / 3 / teachers / new”

這是我的teachers_controller.rb：

class TeachersController < ApplicationController
  def new
    @teacher = Teacher.new
  end

  def create
    @teacher = Teacher.new(teacher_params)
    @teacher.save

    redirect_to school_path(school)
  end

  private

    def teacher_params
      params.require(:teacher).permit(:firstName, :lastName, :middleName)
    end
end

schools_controller.rb：

class SchoolsController < ApplicationController
  def show
    @school = School.find(params[:id])
  end

  def new
    @school = School.new
  end

  def edit
    @school = School.find(params[:id])
  end

  def update
    @school = School.find(params[:id])

    if @school.update(school_params)
      redirect_to @school
    else
      render 'edit'
    end
  end

  def index
    @schools = School.all
  end

  def create
    @school = School.new(school_params)

    if @school.save
      redirect_to schools_path
    else
      render 'new'
    end
  end

  def destroy
    @school = School.find(params[:id])
    @school.destroy

    redirect_to schools_path
  end

  private

    def school_params
      params.require(:school).permit(:name)
    end
end

routes.rb中：

Rails.application.routes.draw do
  resources :schools do
    resources :teachers
  end

  # The priority is based upon order of creation: first created -> highest priority.
  # See how all your routes lay out with "rake routes".

  # You can have the root of your site routed with "root"
  root 'welcome#index'

和老師/ new.html.erb：

<%= form_for :teacher, url: school_teachers_path(school) do |f| %>
  <p>
    <%= f.label :firstName %><br>
    <%= f.text_field :firstName %>
  </p>

  <p>
    <%= f.label :lastName %><br>
    <%= f.text_field :lastName %>
  </p>

  <p>
    <%= f.label :middleName %><br>
    <%= f.text_field :middleName %>
  </p>

  <p>
    <%= f.submit %>
  </p>
<% end %>

Answer 1

由於您的teacher資源嵌套在school資源下，因此您在嘗試創建教師時需要通過學校。

嘗試將teachers_controller.rb new和create操作更改為以下內容：

  def new
    @school = School.find(params[:school_id])
    @teacher = @school.teachers.build
  end

  def create
    @school = School.find(params[:school_id])
    @teacher = @school.teachers.build(params[:teacher])
    @teacher.save
    redirect_to school_path(@school)
  end

然后，將表單更改為：

<%= form_for([@school, @teacher]) do %>
. . .
. . .
<% end %>

Answer 2

我相信這是一個has_many belongs_to協會。 因此，您需要先更改教師控制器創建操作和新操作。

class TeachersController < ApplicationController
 def new
  get_school
  @teacher = @school.teachers.build
 end

 def create
  get_school
  @teacher = @school.teachers.build(teacher_params)
  If @teacher.save
      redirect_to school_path(school)
  else
      render 'new'
  end

 private

  def teacher_params
    params.require(:teacher).permit(:firstName, :lastName, :middleName)
   end
 def get_school
     @school = School.find (params [:school_id])
 end
 end

然后在你的表格中你會做：

  <%= form_for([@school,@teacher]) do |f| %>

希望這會有所幫助

Answer 3

在您的表單中嘗試此操作：

<%= form_for [school, Teacher.new] do |f| %>

您要發布的路徑是針對學校教師的索引：

school_teachers GET    /schools/:school_id/teachers(.:format)   teachers#index