從數組Swift生成按字母排序的字典

Question

我有很多部門的名字

var departments: Array<String>!

我想按字典中的字母順序對數組進行排序，例如字典應該像這樣

var MyDictionary = ["A": ["Affenpoo", "Affenpug", "Affenshire", "Affenwich", "Afghan Collie", "Afghan Hound"], "B": ["Bagle Hound", "Boxer"],
    "C": ["Cagle Cound", "Coxer"]]

部門數組不是靜態的

如何快速生成此詞典？

非常感謝

Answer 1

我的方法是迭代數組並采用每個條目的首字母。 從字典中檢索該字母的數組。 如果為零，則創建一個新數組。 將單詞添加到檢索到的數組中，然后將該數組存儲在字典中。

let departments = ["Affenpoo", "Affenpug", "Affenshire", "Affenwich", "Afghan Collie","Cagle Cound", "Coxer"]
var outputDict=[String:[String]]()

for word in departments {
    let initialLetter=word.substringToIndex(word.startIndex.advancedBy(1)).uppercaseString
    var letterArray=outputDict[initialLetter] ?? [String]()
    letterArray.append(word)
    outputDict[initialLetter]=letterArray
}

print(outputDict)

[“ C”：[“ Cagle Cound”，“ Coxer”]，“ A”：[“ Affenpoo”，“ Affenpug”，“ Affenshire”，“ Affenwich”，“阿富汗牧羊犬”]]

Answer 2

編輯：Paulw11的解決方案更有效

我認為這個問題與swift無關，但是無論如何，請嘗試以下操作：

let a = ["All", "Cat", "red", "gat", "Star sun", "bet you", "Zeta Fog", "Tea", "Fox"]

let b = a.map{ $0.lowercaseString }

let c = b.sort()
let d = c.map{ $0[$0.startIndex.advancedBy(0)]}

var dictionary:[String:[String]] = [:]
let byInitial = d.map{ initial in

    let clustered = c.filter{$0.hasPrefix("\(initial)")}
    dictionary.updateValue(clustered, forKey:"\(initial)")
}
print("\(dictionary)")