[英]Special Characters insert into DB
我在向數據庫中插入特殊字符時遇到問題。 例如,如果字符串為“ \\ kdjfg *&( ^^& %% //”“ dfkjs / Z ?!”,則將“ \\ kdjfg *”插入表中。我不確定為什么整個字符串都沒有得到存在特殊字符時插入
迅速:
let post:NSString = "a=\(a)&b=\(b)&c=\(c)&d=\(d)&username=\(username)";
let url:NSURL = NSURL(string:PassURL)!
let postData = post.dataUsingEncoding(NSUTF8StringEncoding)!
let postLength = String(postData.length)
//Setting up `request` is similar to using NSURLConnection
let request = NSMutableURLRequest(URL: url)
request.HTTPMethod = "POST"
request.HTTPBody = postData
request.setValue(postLength, forHTTPHeaderField: "Content-Length")
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.setValue("application/json", forHTTPHeaderField: "Accept")
let session = NSURLSession.sharedSession()
let task = session.dataTaskWithRequest(request) {urlData, response, reponseError in
if let receivedData = urlData {
let res = response as! NSHTTPURLResponse!;
NSLog("Response code: %ld", res.statusCode);
if (res.statusCode >= 200 && res.statusCode < 300) {
do {
let jsonData = try NSJSONSerialization.JSONObjectWithData(receivedData, options: []) as! NSDictionary
//On success, invoke `completion` with passing jsonData.
completion(jsonData: jsonData, error: nil)
} catch {
//On error, invoke `completion` with NSError.
completion(jsonData: nil, error: nil)
} }
else
{
completion(jsonData: nil, error: nil)
}
}
}
task.resume()
}
的PHP:
header('Content-type: application/json');
if($_POST) {
$username = $_POST['username'];
$a = $_POST['a'];
$b = $_POST['b'];
$c = $_POST['c'];
$d = $_POST['d'];
$mysqli = new mysqli($server_url, $db_user, $db_password, $db_name);
/* check connection */
if (mysqli_connect_errno()) {
error_log("Connect failed: " . mysqli_connect_error());
echo '{"success":0,"error_message":"' . mysqli_connect_error() . '"}';
} else {
$stmt = $mysqli->prepare("insert into testTable (a,b,c,d,postedby) VALUES (?,?,?,?,?)");
$stmt->bind_param("sssss",$a,$b,$c,$d,$username);
$stmt->execute();
$success = $stmt->affected_rows;
$id = $stmt->insert_id;
我不確定這是否是處理特殊字符的正確方法,但這就是我越過目標線的方式。
我使用以下命令填充了iOS中的特殊字符:
a.stringByReplacingOccurrencesOfString("&", withString: "(*)*#@#@$#")
然后在php端,我將( ) #@#@ $#替換為&
$newString = str_replace("(*)*#@#@$#","&",$a);
我希望其他人將來可以提供更好的方法
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