[英]How to call RxJava Observable without immediately subscribing?
我有一個返回字符串模板的java方法。 我想對遠程api進行2次異步調用,每次調用都會返回一個數字,然后我想計算這2個數字的總和,然后將其放入模板中,然后再返回。
所以我有這個Java代碼來實現此任務:
private Observable<Integer> createObservable() {
Observable<Integer> obs = Observable.create(new OnSubscribe<Integer>() {
public void call(Subscriber<? super Integer> t) {
System.out.println("Call with thread : " + Thread.currentThread().getName());
//FAKE CALL TO REMOTE API => THE THREAD IS SLEEPING DURING 4 SECCONDS
try {
Thread.sleep(4000);
} catch (InterruptedException e) {
e.printStackTrace();
}
t.onNext(new Random().nextInt(10));
t.onCompleted();
}
}).subscribeOn(Schedulers.newThread());
return Observable
.merge(obs, obs)
.reduce(new Func2<Integer, Integer, Integer>() {
public Integer call(Integer t1, Integer t2) {
return t1 + t2;
}
});
}
public String retrieveTemplate() {
//I WANT TO START THE WORK OF THE OBSERVABLE HERE BUT I DON'T KNOW HOW TO DO IT
//DO THINGS IN THE MAIN THREAD
//HERE I JUST INITIALIZE A STRING BUT WE COULD IMAGINE I WOULD DO MORE THINGS
String s = "The final Number is {0}";
System.out.println(Thread.currentThread().getName() + " : the string is initialized");
//I WAIT FOR THE OBSERVABLE RESULT HERE
int result = createObservable().toBlocking().first();
return MessageFormat.format(s, result);
}
此代碼的輸出正確(已創建兩個線程來調用遠程api)
main:字符串被初始化
用線程調用:RxNewThreadScheduler-1
用線程調用:RxNewThreadScheduler-2
最終的數字是2
我想在方法retrieveTemplate的開頭調用RxJava Observable(以便盡快調用遠程api),並在調用MessageFormat.format之前等待結果,但是我不知道該怎么做
假設整個創建過程都可行,您可能希望通過轉換可觀察的源將整個計算綁定到訂閱時刻:
public Observable<String> retrieveTemplate() {
return createObservable().map(result -> {
String s = "The final Number is {0}";
System.out.println(Thread.currentThread().getName() + " : the string is initialized");
return MessageFormat.format(s, result);
});
}
當您訂閱retrieveTemplate
可觀察結果時,您實際上開始了整個計算:
// some other place in the code
retrieveTemplate().subscribe(template -> doStuffWithTemplate(template))
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