[英]How to access current user in Django class based view
我無法在基於Django類的視圖中訪問當前登錄的用戶:
models.py:
class Userproject(models.Model):
class Meta:
verbose_name = u'pp'
verbose_name_plural = u'pps'
user = models.ForeignKey(settings.AUTH_USER_MODEL, related_name="project", verbose_name=_("Владелец проекта"))
#user = models.ForeignKey(User, unique=True)
name = models.TextField(u'Название проекта', unique=True)
date_created = models.DateTimeField(u'Дата создания', default=datetime.now(), db_index=True)
date_until = models.DateTimeField(u'Оплачен по', default=datetime.now(), db_index=True)
views.py:
@login_required
class UserprojectList(ListView):
context_object_name = 'userproject_list'
queryset = Userproject.objects.filter(user=self.request.user)
template_name = 'userproject_list.html'
當我導航到url時,我看到錯誤: 名稱'self'未定義
如果我將self.request.user更改為request.user,則錯誤為:name'request '未定義
請注意,沒有用戶過濾視圖正在工作並顯示數據django 1.8.5
你可以覆蓋get_queryset
:
@login_required
class UserprojectList(ListView):
context_object_name = 'userproject_list'
template_name = 'userproject_list.html'
def get_queryset(self):
return Userproject.objects.filter(user=self.request.user)
你也不能在類上使用裝飾器 ,所以你必須寫這樣的東西:
from django.utils.decorators import method_decorator
class UserprojectList(ListView):
context_object_name = 'userproject_list'
template_name = 'userproject_list.html'
@method_decorator(login_required)
def dispatch(self, *args, **kwargs):
return super(UserprojectList, self).dispatch(*args, **kwargs)
def get_queryset(self):
return Userproject.objects.filter(user=self.request.user)
我會嘗試在__init__
方法中執行此操作:
@login_required
class UserprojectList(ListView):
context_object_name = 'userproject_list'
template_name = 'userproject_list.html'
def __init__(self, *args, **kwargs):
super(UserprojectList, self).__init__(*args, **kwargs)
self.queryset = Userproject.objects.filter(user=self.request.user)
我認為在基於類的視圖中,您需要覆蓋get_queryset()方法,以便能夠訪問附加到視圖實例的self.request對象,而不是在類級別執行此操作。 Classy Class-Based Views網站提供了更多信息: http : //ccbv.co.uk/projects/Django/1.8/django.views.generic.list/ListView/
@ pythad的回答是正確的。 但是在Django 1.9+上,您可以使用django.contrib.auth.mixins.LoginRequiredMixin替換舊式的@login_required裝飾器,而不是dispatch
方法。
from django.contrib.auth.mixins import LoginRequiredMixin
class UserprojectList(LoginRequiredMixin, ListView):
context_object_name = 'userproject_list'
template_name = 'userproject_list.html'
def get_queryset(self):
return Userproject.objects.filter(user=self.request.user)
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