返回多個ArrayList <ArrayList<String> &gt;

Question

我有一個方法，使4個數組列表的數組列表，我試圖找出要返回的數據。 我知道它不會讓我做不止一個return語句，所以有沒有辦法將ArrayLists組合在一起以返回？

public class sys {
public static void main(String[] args) 
{
    try 
    {
        FileInputStream file = new FileInputStream(new File("data/database.xlsx"));
        XSSFWorkbook mainDB = new XSSFWorkbook(file);

        int i = 0;
        do
        {
            ArrayList<ArrayList<String>> sheet1 = new ArrayList<ArrayList<String>>();
            ArrayList<ArrayList<String>> sheet2 = new ArrayList<ArrayList<String>>();
            ArrayList<ArrayList<String>> sheet3 = new ArrayList<ArrayList<String>>();
            ArrayList<ArrayList<String>> sheet4 = new ArrayList<ArrayList<String>>();
            ArrayList<String> cellArray = new ArrayList<String>();      
            XSSFSheet sheet = mainDB.getSheetAt(i);
            Iterator<Row> rowIterator = sheet.iterator();
            rowIterator.next();
            while(rowIterator.hasNext())
            {
                Row row = rowIterator.next();
                if(row.getRowNum()==0)
                {
                       continue; //skip the first row
                }
                else
                {
                    Iterator<Cell> cellIterator = row.cellIterator();
                    while(cellIterator.hasNext())
                    {
                        Cell cell = cellIterator.next();
                        //switch(cell.getCellType()) 
                        {
                            String c = "";
                            if(cell.getCellType() == Cell.CELL_TYPE_NUMERIC)
                            {
                                c = Integer.toString((int)(cell.getNumericCellValue()));
                            }
                            if(cell.getCellType() == Cell.CELL_TYPE_STRING)
                            {
                                c = cell.getStringCellValue();
                            }
                            cellArray.add(c);
                        }
                    }
                    if (i==0);
                    {
                        sheet1.add(cellArray);
                    }
                    if (i==1);
                    {
                        sheet2.add(cellArray);
                    }
                    if (i==2);
                    {
                        sheet3.add(cellArray);
                    }
                    if (i==3);
                    {
                        sheet4.add(cellArray);
                    }
                }
            }
            return sheet1;
            return sheet2;
            return sheet3;
            return sheet4;

            i++;

        } 
        while (i<4);
        file.close();


    }

    catch (FileNotFoundException error1) {
        error1.printStackTrace();
    } 

    catch (IOException error2) {
        error2.printStackTrace();
    }
}

}

Answer 1

如果您有一定數量的ArrayLists，那么最有效的方法是創建一個ArraysLists數組，如下所示：

ArrayList<ArrayList<String>>[] array = new ArrayList<ArrayList<String>>[] {arrayList1, arrayList2, arrayList3, arrayList4};

或如下：

ArrayList<ArrayList<String>>[] array = new ArrayList<ArrayList<String>>[4];
array[0] = arrayList1;
array[1] = arrayList2;
array[2] = arrayList3;
array[3] = arrayList4;

編輯：正如評論所指出，上述實際上是不可能的！ 這是更新的解決方案：

    ArrayList<ArrayList<String>>[] array = (ArrayList<ArrayList<String>>[])  Array.newInstance(arrayList1.getClass(), arrayList1.size());

*假設arrayList1是OP提到的ArrayLists之一

Answer 2

public class ArrayListUtils {

    public static void main(String[] args) {
        ArrayListUtils listUtils = new ArrayListUtils();

        ArrayList<String> one = new ArrayList<>();
        one.add("A");
        one.add("B");

        ArrayList<String> two = new ArrayList<>();
        two.add("AA");
        two.add("BA");

        ArrayList<String> three = new ArrayList<>();
        three.add("AAA");
        three.add("BAA");

        ArrayList<String> four = new ArrayList<>();
        four.add("AAAA");
        four.add("BAAA");

        //If you need ArrayList of four ArrayList<String> object
        ArrayList<ArrayList<String>> arrayList = listUtils.getArrayList(one, two, three, four);

        //If you need List of four ArrayList<String> object
        List<ArrayList<String>> list = listUtils.getList(one, two, three, four);

    }

    /*
     ArrayList<String>... strings :: means varargs 
     */
    public ArrayList<ArrayList<String>> getArrayList(ArrayList<String>... strings) {
        ArrayList<ArrayList<String>> list = new ArrayList<>();
        list.addAll(Arrays.asList(strings));
        return list;
    }

    public List<ArrayList<String>> getList(ArrayList<String>... strings) {
        return Arrays.asList(strings);
    }
}