Symfony中可能需要不同的類型

Question

我正在嘗試使用Symfony和Doctrine創建一個表單。 我使用Doctrine創建了一個Job類，並在mysql中創建了一個與其相關的表。 它還制作了JobType和JobController，以及Routing工具。

我可以訪問列出了作業的索引頁面，但是無法訪問新的條目頁面。

這是用於創建表單的文件。

JobController.php

   <?php

namespace AppBundle\Controller;

use Symfony\Component\HttpFoundation\Request;
use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Method;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Route;
use AppBundle\Entity\Job;
use AppBundle\Form\JobType;

/**
 * Job controller.
 *
 * @Route("/job")
 */
class JobController extends Controller
{
    /**
     * Lists all Job entities.
     *
     * @Route("/", name="job_index")
     * @Method("GET")
     */
    public function indexAction()
    {
        $em = $this->getDoctrine()->getManager();

        $jobs = $em->getRepository('AppBundle:Job')->findAll();

        return $this->render('job/index.html.twig', array(
            'jobs' => $jobs,
        ));
    }

    /**
     * Creates a new Job entity.
     *
     * @Route("/new", name="job_new")
     * @Method({"GET", "POST"})
     */
    public function newAction(Request $request)
    {
        $job = new Job();
        $jobType = new JobType();
        $form = $this->createForm($jobType, $job);
        $form->handleRequest($request);

        if ($form->isSubmitted() && $form->isValid()) {
            $em = $this->getDoctrine()->getManager();
            $em->persist($job);
            $em->flush();

            return $this->redirectToRoute('job_show', array('id' => $job->getId()));
        }

        return $this->render('job/new.html.twig', array(
            'job' => $job,
            'form' => $form->createView(),
        ));
    }

    /**
     * Finds and displays a Job entity.
     *
     * @Route("/{id}", name="job_show")
     * @Method("GET")
     */
    public function showAction(Job $job)
    {
        $deleteForm = $this->createDeleteForm($job);

        return $this->render('job/show.html.twig', array(
            'job' => $job,
            'delete_form' => $deleteForm->createView(),
        ));
    }

    /**
     * Displays a form to edit an existing Job entity.
     *
     * @Route("/{id}/edit", name="job_edit")
     * @Method({"GET", "POST"})
     */
    public function editAction(Request $request, Job $job)
    {
        $deleteForm = $this->createDeleteForm($job);
        $editForm = $this->createForm(new JobType(), $job);
        $editForm->handleRequest($request);

        if ($editForm->isSubmitted() && $editForm->isValid()) {
            $em = $this->getDoctrine()->getManager();
            $em->persist($job);
            $em->flush();

            return $this->redirectToRoute('job_edit', array('id' => $job->getId()));
        }

        return $this->render('job/edit.html.twig', array(
            'job' => $job,
            'edit_form' => $editForm->createView(),
            'delete_form' => $deleteForm->createView(),
        ));
    }

    /**
     * Deletes a Job entity.
     *
     * @Route("/{id}", name="job_delete")
     * @Method("DELETE")
     */
    public function deleteAction(Request $request, Job $job)
    {
        $form = $this->createDeleteForm($job);
        $form->handleRequest($request);

        if ($form->isSubmitted() && $form->isValid()) {
            $em = $this->getDoctrine()->getManager();
            $em->remove($job);
            $em->flush();
        }

        return $this->redirectToRoute('job_index');
    }

    /**
     * Creates a form to delete a Job entity.
     *
     * @param Job $job The Job entity
     *
     * @return \Symfony\Component\Form\Form The form
     */
    private function createDeleteForm(Job $job)
    {
        return $this->createFormBuilder()
            ->setAction($this->generateUrl('job_delete', array('id' => $job->getId())))
            ->setMethod('DELETE')
            ->getForm()
        ;
    }
}

JobType.php

namespace AppBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;

class JobType extends AbstractType
{
    /**
     * @param FormBuilderInterface $builder
     * @param array $options
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('category', 'string')
            ->add('type', 'string')
            ->add('company', 'string')
            ->add('logo', 'string')
            ->add('url', 'string')
            ->add('position', 'string')
            ->add('location', 'string')
            ->add('desciption', 'text')
            ->add('how_to_apply', 'text')
            ->add('token', 'string')
            ->add('is_public', 'boolean')
            ->add('is_activated', 'boolean')
            ->add('email', 'string')
            ->add('expires_at', 'datetime')
            ->add('created_at', 'datetime')
            ->add('updated_at', 'datetime')
        ;
    }

    /**
     * @param OptionsResolver $resolver
     */
    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults(array(   
            'data_class' => 'AppBundle\Entity\Job'
        ));
    }   

    /**
     * Mandatory in Symfony2
     * Gets the unique name of this form.
     * @return string
     */
    public function getName()
    {
        return 'add_job';
    }
}

這是我收到的錯誤，謝謝！

編輯：app / config / services.yml的內容

parameters:
#    parameter_name: value

services:
#    service_name:
#        class: AppBundle\Directory\ClassName
#        arguments: ["@another_service_name", "plain_value", "%parameter_name%"]

Answer 1

$editForm = $this->createForm(new JobType(), $job);

這在Symfony 3中不再可能。在Symfony 3中，您始終必須為表單類型傳遞完全合格的類名：

$editForm = $this->createForm(JobType::class, $job);

另外，在表單類型中，您要傳遞類型名稱，而不是類型類的FQCN。

Symfony 3剛剛發布了第一個BETA，這意味着它非常前沿。 此外，Symfony 3的教程幾乎為零（因為它的邊緣非常差）。 您正在閱讀Symfony 2教程，因此建議您安裝Symfony 2而不是3。