PHP准備語句連接：來自while循環的“逗號”，“和”和“句點”

Question

我正在嘗試從MySQL查詢構建一個句子。 我相信我有連接部分工作，因為我已經替換了靜態數組。可能有人指導我正確的方向，我的while循環看起來像生成所需的數組？ 如何從我的mysql語句創建關聯數組？

$query = "SELECT name, dob FROM children WHERE personal_id = ?";
$statement = $db->prepare($query);
$statement->bind_param('i', $_SESSION['mysqlID']);
$statement->bind_result($name, $dob);
$statement->execute();

// Store the results
$statement->store_result();

// Get the number of rows
$num_of_rows = $statement->num_rows;


**//I believe my problem lies in this array ?**
$m_children = [];
while ($statement->fetch()) {
  $m_children[] =  $name;
  $m_children[] .=  $dob;
}

$num_children = intval($num_of_rows);
$children = [];

foreach ($m_children as $k => $v) {
  $dob = strtotime($dob[$k]);
  $children[] = "$v, born on {$dob}";
}

$tmp = array_pop($children);

  if ($num_children > 1) {
    $children_type = 'children';
    $children = join(', ', $children) . ' and ' . $tmp;
  } else {
    $children_type = 'child';
    $children = $tmp;
  }

$children = "<p>I have the following ". $children_type .": ". $children .".</p>";

Answer 1

總體而言，您的代碼看起來沒問 語法部分肯定是固定的（彈出最后一個元素，用逗號連接其余部分......）

如您所料，您的問題代碼是您標記的部分。

//I believe my problem lies in this array ?
$m_children = [];
while ($statement2->fetch()) {
  $m_children[] =  $name;
  $m_children[] .=  $dob;
}

$num_children = intval($num_of_rows);
$children = [];

foreach ($m_children as $k => $v) {
  $dob = strtotime($dob[$k]);
  $children[] = "$v, born on {$dob}";
}

---

這是一個建議的改進：

$children = [];
while( $statement2->fetch()) {
    $children[] = $name." born on ".date("d/M/Y",strtotime($dob));
}
$num_children = count($children);

沒有必要對數據進行兩次傳遞，您需要格式化出生日期（否則您只需要一個時間戳）。 這段代碼可以繼續你的語法格式，這對我來說似乎沒問題。