MySQL 選擇表 2 上的多行，表 1 中的兩個不同 Id 導致一行作為兩個不同的字段

Question

是否有可能僅在一個 MySQL 查詢中將所需的結果（如下）返回到一行中？

其中表 1 中 id=1

表格1

|------|----------|----------|
| id   | refIdOne | refIdTwo |
|------|----------|-----------
| 1    | 1        | 2        |
|------|----------|-----------

列“refIdOne”和“refIdTwo”指的是表 2“id”列

表 2

|------|------------------|
| id   | text             |
|------|------------------|
| 1    | cheese           |
| 2    | made with milk   |
|------|------------------|

ONE ROW 中返回的所需結果，帶有名為“subject”和“description”的自定義 AS 列：

|----------|-----------------|
| subject  | description     |
|----------|-----------------|
| cheese   | made with milk  |

? 非常感謝您的幫助

* 編輯：答案是 *

select t21.text as subject, t22.text as description
from Table1 as t1
join Table2 as t21 on t1.refidone = t21.id
join Table2 as t22 on t1.refidtwo = t22.id
where t1.id = 1

Answer 1

表 2 必須兩次連接到表 1。

select t21.text as subject, t22.text as description
from table1 t1
join table2 t21 on t1.refidone = t21.id
join table2 t22 on t1.refidtwo = t22.id

Answer 2

您需要執行Self join 。 加入表Table2 。 使用Table1 ID兩次。 refIdOne和Table1 。 refIdTwo

select t2.text as subject, t3.text as description 
from Table1  t1 
Left join Table2 t2 on t1.refIdOne = t2.id
Left join Table2 t3 on t1.refIdTwo = t2.id

Answer 3

沒有連接

SELECT
(SELECT text FROM Table2 WHERE id = (SELECT refIdOne FROM Table1 WHERE id = 1) ) AS name,
(SELECT text FROM Table2 WHERE id = (SELECT refIdTwo FROM Table1 WHERE id = 1) ) AS description