根據MongoDB中的條件從嵌入式文檔合並數組

Question

我收集了如下的學生詳細信息：

  {
    "Student_id": 1,
    "StudentName": "ABC",
    "TestDetails": [{
            "SubtestName":"Reading", "TestSeq":1, "SubTestDetails":1, 
            "Scores":[{"ScoreType":"YY","ScoreValue":"100"},{"ScoreType":"XX","ScoreValue":"100"},
            {"ScoreType": "ZZ","ScoreValue":"100"}]}]
  ,
    "TestDetails": [{
            "SubtestName":"Writing", "TestSeq":1, "SubTestDetails":2, 
            "Scores":[{"ScoreType":"YY","ScoreValue":"200"},{"ScoreType":"XX","ScoreValue":"200"},
            {"ScoreType": "ZZ","ScoreValue":"200"}]}]
  ,
    "TestDetails": [{
            "SubtestName":"Listning", "TestSeq":2, "SubTestDetails":3, 
            "Scores":[{"ScoreType":"YY","ScoreValue":"300"},{"ScoreType":"XX","ScoreValue":"300"},
            {"ScoreType": "ZZ","ScoreValue":"300"}]}]
  ,
    "TestDetails": [{
            "SubtestName":"Speaking", "TestSeq":2, "SubTestDetails":4, 
            "Scores":[{"ScoreType":"YY","ScoreValue":"400"},{"ScoreType":"XX","ScoreValue":"400"},
            {"ScoreType": "ZZ","ScoreValue":"400"}]}]
  ,
    "TestDetails": [{
            "SubtestName":"Smartness", "TestSeq":3, "SubTestDetails":5, 
            "Scores":[{"ScoreType":"YY","ScoreValue":"500"},{"ScoreType":"XX","ScoreValue":"500"},
            {"ScoreType": "ZZ","ScoreValue":"500"}]}]
  },

  {
    "Student_id": 2,
    "StudentName": "XYZ",
    "TestDetails": [{
            "SubtestName":"Smartness", "TestSeq":1, "SubTestDetails":1, 
            "Scores":[{"ScoreType":"YY","ScoreValue":"100"},{"ScoreType":"XX","ScoreValue":"100"},
            {"ScoreType": "ZZ","ScoreValue":"100"}]}]
  ,
    "TestDetails": [{
            "SubtestName":"Writing", "TestSeq":1, "SubTestDetails":2, 
            "Scores":[{"ScoreType":"YY","ScoreValue":"200"},{"ScoreType":"XX","ScoreValue":"200"},
            {"ScoreType": "ZZ","ScoreValue":"200"}]}]
  ,
    "TestDetails": [{
            "SubtestName":"Listning", "TestSeq":2, "SubTestDetails":3, 
            "Scores":[{"ScoreType":"YY","ScoreValue":"300"},{"ScoreType":"XX","ScoreValue":"300"},
            {"ScoreType": "ZZ","ScoreValue":"300"}]}]
  ,
    "TestDetails": [{
            "SubtestName":"Speaking", "TestSeq":2, "SubTestDetails":4, 
            "Scores":[{"ScoreType":"YY","ScoreValue":"400"},{"ScoreType":"XX","ScoreValue":"400"},
            {"ScoreType": "ZZ","ScoreValue":"400"}]}]
  ,
    "TestDetails": [{
            "SubtestName":"Reading", "TestSeq":3, "SubTestDetails":5, 
            "Scores":[{"ScoreType":"YY","ScoreValue":"100"},{"ScoreType":"XX","ScoreValue":"100"},
            {"ScoreType": "ZZ","ScoreValue":"1000"}]}]
  }, 
  .
  .
  .
)

如何創建聚合查詢以生成如下文檔：

{Student:1, "TestSeq" : 1, [{Subtest_name: Reading},{Subtest_name: Writing}]},
{Student:1,"TestSeq" :  2, [{Subtest_name: Listning},{Subtest_name: Speaking}]},
{Student:1, "TestSeq" : 3, [{Subtest_name: Smartness}]},
{Student:2, "TestSeq" : 1, [{Subtest_name: Smartness},{Subtest_name: Writing}]},
{Student:2, "TestSeq" : 2, [{Subtest_name: Listning},{Subtest_name: Speaking}]},
{Student:2, "TestSeq" : 3, [{Subtest_name: Reading}]},
{Student:3, "TestSeq" : 1, [{Subtest_name: Subtest1},{Subtest_name: Subtest2}]},
{Student:3, "TestSeq" : 2, [{Subtest_name: Subtest3},{Subtest_name: Subtest4}]},
{Student:3, "TestSeq" : 3, [{Subtest_name: Subtest5}]}

邏輯是根據TestSeq值對子測試名稱進行組合/分組。 例如，為TestSeq = 1組合了子測試名稱，對於值2，它位於第二行，對於每個學生，最后一個子測試名稱是3。

我該如何實施？

我嘗試了如下-

db.students.aggregate([ 
{$unwind: "$SubtestAttribs"},
{ $project: { student_name: 1, student_id : 1,
 print_ready : "$SubtestAttribs.TestSeq",
 Subtest_names :$SubtestAttribs.SubtestName" } } ])

但是我無法根據條件形成數組。 上面的代碼段提供了每個測試序列的數據。 但是如何根據測試序列來組合兩個子測試名稱呢？

Answer 1

注意：我做幾個假設，因為您的問題中包含一些非法的JSON。 讓我知道我猜錯了。 另外，我現在不在裝有Mongo的計算機上，因此我可能會遇到一些語法問題。

db.students.aggregate([
{ $unwind: "$TestDetails" },
{
    $group:{
        _id: { Student: "$Student_id", TestSeq: "$TestDetails.TestSeq},
        Subtest_names: { $addToSet: "$TestDetails.Subtestname" }
    }
},
{
    $project:{
        Student: "$_id.Student",
        TestSeq: "$_id.TestSeq,
        Subtest_names: "$Subtest_names"
    }
}
])