mysql數據透視表按日期

Question

我正在嘗試按天顯示包含特定列的總和的付款表的結果；

payment id | payment_actual_timestamp | payment type | amount
1          | 2015-11-23 13:01:20      | AUTH         | 0.16
2          | 2015-11-23 13:07:20      | AUTH         | 23.65
3          | 2015-11-24 08:07:20      | VOID         | 19.24
4          | 2015-11-24 13:45:20      | AUTH         | 0.65
5          | 2015-11-24 16:34:10      | REFUND       | 1.20
6          | 2015-11-25 13:07:20      | SETTLE       | 4.40

我想顯示的是以下內容；

Date       | SETTLE | AUTH | VOID | REFUND
2015-11-23 | 0.00   | 23.81| 0.00 | 0.00
2015-11-24 | 0.00   | 0.65 | 19.24| 1.20
2015-11-25 | 4.40   | 0.00 | 0.00 | 0.00

有沒有辦法做到這一點？

非常感謝。

Answer 1

一種選擇是對sum和case使用conditional aggregation ：

select date(payment_actual_timestamp), 
   sum(case when payment_type = 'SETTLE' then amount end) settleamt,
   sum(case when payment_type = 'AUTH' then amount end) authamt,
   sum(case when payment_type = 'VOID' then amount end) voidamt,
   sum(case when payment_type = 'REFUND' then amount end) refundamt
from yourtable
group by date(payment_actual_timestamp)