如何使用php為表的特定列中的所有行建立超鏈接

Question

我希望我問對了； 我是一個初級的 PHP 程序員。 這是我的部分代碼...

$con = mysqli_connect("localhost","root","","project");

mysqli_select_db($con,"project");

$result = mysqli_query($con,"select distinct drug from drugs");

while($row = mysqli_fetch_array($result))
{
    echo "<a href='review10.php'>";
    echo $row['drug'];
    echo "</a>";
}
echo "hai";

在這里，當顯示葯物列表時，當用戶單擊任何葯物名稱時，應顯示所有輸入葯物名稱的客戶及其用途的詳細信息。 我正在使用 PHP/MYSQL/WAMP。

Answer 1

使用此代碼

$con = mysqli_connect("localhost","root","","project");

mysqli_select_db($con,"project");

$result = mysqli_query($con,"select distinct drug from drugs");

while($row = mysqli_fetch_array($result))
{
    echo "<a href='review10.php'> '".$row['drug']."'</a>";
}