如何使用角度使用AM / PM獲得12小時格式？

Question

 $scope.timePickerObject12Hour = { inputEpochTime: ((new Date()).getHours() * 60 * 60 + 3600), //Optional step: 15, //Optional format: 12, //Optional //titleLabel: '12-hour Format', //Optional closeLabel: 'Close', //Optional setLabel: 'Set', //Optional setButtonType: 'button-positive', //Optional closeButtonType: 'button-stable', //Optional callback: function (val) { //Mandatory timePicker12Callback(val); } }; function timePicker12Callback(val) { if (typeof (val) === 'undefined') { console.log('Time not selected'); } else { $scope.timePickerObject12Hour.inputEpochTime = val; console.log(val); var selectedTime = new Date(val * 1000); } } 

我已經使用了角度和離子應用程序。在這里我遵循了這個gitup https://github.com/rajeshwarpatlolla/ionic-timepicker作為時間選擇器。當我選擇時間（例如我選擇了5pm）控制台時，我正在獲得價值61200這個或選定的時期是：61200，時間是17：0（在UTC中）我如何將其轉換為AM / PM格式的12hrs格式，任何人都可以幫助我

$scope.timePickerObject12Hour.inputEpochTime = val;
        console.log(val);
        var selectedTime = new Date(val * 1000);
        console.log('Selected epoch is : ', val, 'and the time is ', selectedTime.getUTCHours(), ':', selectedTime.getUTCMinutes(), 'in UTC');

Answer 1

例如：

var yourDateObject = new Date();
var amPmHour = $filter('date')(yourDateObject, 'hh');

不要忘記為此調用$ filter模塊。

從Angularjs Date文檔