[英]MYSQL php database insert including image upload
我試圖將用戶輸入插入數據庫。 我想在廣告表中添加標題和描述,在圖片表中添加圖像。 到目前為止,這是我想出的,但是根本沒有用。 這是一個posthandler.php頁面,當用戶按下Submit時將被調用。 頂部的變量從html頁面分配了輸入名稱。 目前,我的圖片數據庫中同時包含路徑名和Blob,以查看哪個選項最有效。
請幫忙
<?php
session_start();
echo "You are signed in as ". $_SESSION['username'];
include 'mysql.php';
$title='title';
$des='des';
$image='image';
if(isset($_POST['submit'])) {
$error = "";
if (!empty($_POST['title'])) {
$title= $_POST['title'];
} else {
$error = "Please enter a title for your Ad. <br />";
}
if (!empty($_POST['des'])) {
$des = $_POST['des'];
} else {
$error = "Please describe your item <br />";
}
if (!empty($_POST['image'])) {
$image=addslashes($_FILES['image']['tmp_name']);
$name=addslashes($_FILES['image']['name']);
$image=file_get_contents($image);
$image=base64_encode($image);
$filepath = "images/".$filename;
move_uploaded_file($filetmp,$filepath);
$image = $_POST['image'];
} else {
}
if (empty($error)) {
$conn= mysql_connect("localhost","km","data");
if (!$conn){
die ("Failed to connect to MySQL: " . mysql_error());
mysql_select_db("mdb_km283",$conn);
$sql = "INSERT INTO Advert (title, description) VALUES ('$_POST[title]','$_POST[des]')";
$sql2 = "INSERT INTO Pictures(image, Path) VALUES ('$_POST[image]' $filepath)";
mysql_query( $sql,$sql2, $conn );
//mysql_query( $sql2,$conn );
mysql_close($conn);
echo 'Upload successfull';
}
}
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN"
"http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html version="-//W3C//DTD XHTML 1.1//EN"
xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.w3.org/1999/xhtml
http://www.w3.org/MarkUp/SCHEMA/xhtml11.xsd"
>
<head>
<link rel="stylesheet" type=text/css" href="stylesheet.css">
<a href="signout.php">Logout</a>
<h1>ERROR - Please go back and fix the below:</h1>
</head>
<body>
<?php
if (!empty($error)) {
echo'<p class="error"><strong>Upload failed. Please go back and fix the below <br/> The following error(s) returned:</strong><br/>' . $error . '</p>';
} else {
echo '<meta http-equiv="refresh" content="0; URL=user.php">';
}
?>
</body>
</html>
$filename = $_FILES['image']['name'];
$filepath = 'image/' . $filename;
$filetmp = $_FILES['image']['temp_name'];
$result = move_uploaded_file($filetmp,$filepath);
if(!$result)
echo "Photo field was blank";
else
echo "uploaded";
然后在這里寫你的mysql代碼....
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