[英]how to group data by more than two factors in R
我有一個如下所示的數據集。 在實際數據集中,有8619行。
Athlete Competing Country Year Total Medals
Michael Phelps United States 2012 6
Alicia Coutts Australia 2012 5
Missy Franklin United States 2012 5
Brian Leetch United States 2002 1
Mario Lemieux Canada 2002 1
Ylva Lindberg Sweden 2002 1
Eric Lindros Canada 2002 1
Ulrica Lindström Sweden 2002 1
Shelley Looney United States 2002 1
我想按國家/地區,年份和獎牌總數重新排列這些數據。
我想要結果
Country Year SumOfMedals
United States 2012 11
United States 2002 2
...
by(newmd$Total.Medals, newmd$Year, FUN=sum)
by(md$Total.Medals, md$Competing.Country, FUN=sum)
我厭倦了通過爭論使用,但仍然堅持。 你們有人可以幫助我嗎?
或者使用data.table
,我們將'data.frame'轉換為'data.table'( setDT(df1)
),按'Competing_Country','Year'分組,通過變量得到'Total_Medals and then
命令`的sum
出於興趣。
library(data.table)
setDT(df1)[,list(SumOfMedals = sum(Total_Medals)),
by = .(Competing_Country, Year)
][order(-Competing_Country, -Year, -SumOfMedals)]
或者使用dplyr
,我們使用相同的方法。
library(dplyr)
df1 %>%
group_by(Competing_Country, Year) %>%
summary(SumOfMedals = sum(Total_Medals) %>%
arrange(desc(Competing_Country), desc(Year), desc(SumOfMedals))
df1 <- structure(list(Athlete = c("Michael Phelps", "Alicia Coutts",
"Missy Franklin", "Brian Leetch", "Mario Lemieux", "Ylva Lindberg",
"Eric Lindros", "Ulrica Lindström", "Shelley Looney"), Competing_Country = c("United States",
"Australia", "United States", "United States", "Canada", "Sweden",
"Canada", "Sweden", "United States"), Year = c(2012L, 2012L,
2012L, 2002L, 2002L, 2002L, 2002L, 2002L, 2002L), Total_Medals = c(6L,
5L, 5L, 1L, 1L, 1L, 1L, 1L, 1L)), .Names = c("Athlete", "Competing_Country",
"Year", "Total_Medals"), class = "data.frame", row.names = c(NA,
-9L))
你可以使用aggregate
很容易地做到這一點,以獲得獎牌數量的總和:
md2 <- aggregate(cbind(SumOfMedals = Total.Medals) ~ Competing.Country + Year),
data = md,
FUN = sum)
下一步是通過Competing.Country
和SumOfMedals
對md2
進行排序,這是使用order
函數完成的:
md2 <- md2[order(Competing.Country, -SumOfMedals),]
全部完成。
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