[英]Spring MVC controllers not loaded
我對Spring無法拿起控制器有疑問。 我使用過maven webapp原型在Eclipse中創建一個項目,並且效果很好-我可以訪問index.jsp頁面。 當我將Spring添加到項目中時,問題開始了。 (上下文,控制器等)
我正在使用Eclipse Mars,Tomcat 8,maven 3.3.3和Spring 4.2.2
這是我在日志中看到的內容(可能只有第三行很重要):
Looking for matching resources in directory tree [C:\Users\dima\spring_workspace\.metadata\.plugins\org.eclipse.wst.server.core\tmp1\wtpwebapps\cte\WEB-INF\classes\com\company\dept\demo\cte\controller]
Searching directory [C:\Users\dima\spring_workspace\.metadata\.plugins\org.eclipse.wst.server.core\tmp1\wtpwebapps\cte\WEB-INF\classes\com\company\dept\demo\cte\controller] for files matching pattern [C:/Users/dima/spring_workspace/.metadata/.plugins/org.eclipse.wst.server.core/tmp1/wtpwebapps/cte/WEB-INF/classes/com/company/dept/demo/cte/controller/**/*.class]
Resolved location pattern [classpath*:com/company/dept/demo/cte/controller/**/*.class] to resources []
而不是像
INFO: Mapped URL path ...
結果,當我嘗試打開網頁時得到404。 這些是文件:
調度員servlet.xml中
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:ldap="http://www.springframework.org/schema/ldap"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/ldap
http://www.springframework.org/schema/ldap/spring-ldap.xsd">
<context:component-scan base-package="com.company.dept.demo.cte.controller" />
<mvc:annotation-driven/>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
web.xml中
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
這是我的控制器:
package com.company.dept.demo.cte.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;
@Controller
@RequestMapping("/pid")
public class PidController {
@RequestMapping(value="/hello")
public ModelAndView helloWorld() {
ModelAndView mav = new ModelAndView("pidHello");
mav.addObject("message", "hello world");
return mav;
}
}
嘗試訪問localhost:8080 / cte / pid / hello時返回404,日志顯示:
DispatcherServlet with name 'dispatcher' processing GET request for [/cte/pid/hello]
Looking up handler method for path /pid/hello
Did not find handler method for [/pid/hello]
No mapping found for HTTP request with URI [/cte/pid/hello] in DispatcherServlet with name 'dispatcher'
謝謝。
更新: WAR文件是正確的,但是由於某種原因,它沒有復制到Tomcat控制器類中。
是否是完整的web.xml,因為您必須將調度程序servlet引用添加到web.xml中,如下所示-
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
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