編譯器給我一個“無法達到的陳述”錯誤

Question

這是我的代碼中的一種方法，當我嘗試編譯它時，拋出“無法到達的語句”錯誤。

public static boolean whoareyou(String player)
{
    boolean playerwhat;
    if (player.equalsIgnoreCase("Player 1"))
    {
        return true;
    }
    else
    {
        return false;
    }
    return playerwhat;
}

確切的錯誤是：

java:82: error: unreachable statement
                return playerwhat;
                ^

然后，我嘗試使用以下返回的布爾值：

public static int questions(int diceroll, int[] scorep1)
{
 String wanttocont = " ";
 boolean playerwhat;
 for (int i = 0; i <= 6; i++)
 {
   while (!wanttocont.equalsIgnoreCase("No"))
   {
    wanttocont = input("Do you wish to continue?"); 
    // boolean playerwhat; wasn't sure to declare here or outside loop
    if (diceroll == 1)
    {
       String textinput = input("What's 9+10?");
       int ans1 = Integer.parseInt(textinput);
       output("That's certainly an interesting answer.");
       if (ans1 == 19)
       {
          if (playerwhat = true)
          {
             output("Fantastic answer player 1, that's correct!");
             diceroll = dicethrow(diceroll);
             scorep1[0] = scorep1[0] + diceroll;
             output("Move forward " + diceroll + " squares. You are on square " + scorep1[0]);
          }
          else if (playerwhat = false)
          {
             output("Fantastic answer player 2, that's correct!");
             diceroll = dicethrow(diceroll);
             scorep1[1] = scorep1[1] + diceroll;
             output("Move forward " + diceroll + " squares. You are on square " + scorep1[1]);
          }
    } // END if diceroll is 1
   } // END while wanttocont
 } // END for loop
} // END questions

我不確定上面的代碼是否與問題有關，但我只是想說明我要如何處理拋出錯誤的布爾值。 謝謝。

Answer 1

return playerwhat; 永遠無法達到，因為if或else子句將返回true或false 。 因此，您應該刪除此語句。 playerwhat變量。

順便說一句，您的方法可以用一種內襯方法代替：

public static boolean whoareyou(String player)
{
    return player.equalsIgnoreCase("Player 1");
}

我將此方法重命名為更具描述性的名稱，例如isFirstPlayer 。

編輯：

您永遠不會稱呼whoareyou為您的questions方法。 您應該稱呼它為：

更換

if (playerwhat = true) // this is assigning true to that variable, not comparing it to true

同

if (whoareyou(whateverStringContainsTheCurrentPlayer)) {
    ..
} else {
    ...
}

Answer 2

只是這樣更新代碼

public static boolean whoareyou(String player)
{
    boolean playerwhat;
    if (player.equalsIgnoreCase("Player 1"))
    {
        playerwhat = true;
    }
    else
    {
        playerwhat = false;
    }
    return playerwhat;
}

Answer 3

嘗試這個：

public static boolean whoareyou(String player)
{
    return player.equalsIgnoreCase("Player 1");
}

您遇到了問題，因為：

 return player what; 

永遠不會到達。 您可以通過“ if”部分或“ else”部分退出函數。