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在mysql查詢錯誤中有子句

[英]having clause in mysql query error

我正在嘗試根據lat和lng獲取最近的位置,但我想在查詢中添加距離<5子句。

但我可以在哪里使用。??

select p.id, p.name, p_i.image as image, 
( 3959 * acos( cos( radians(26.916279) ) * 
cos( radians( lat ) ) * 
cos( radians( lng ) - radians(75.8082) ) + 
sin( radians(26.916279) ) * 
sin( radians( lat ) ) ) ) AS distance 
from `places` as p 
inner join `place_images` as p_i 
on p.`id` = p_i.`place_id` 
where p.`city_id` = '1' 
and p.status = 'active' 
and p_i.display_order = '1' 
limit 0, 5

目前的結果

在此輸入圖像描述

試試這個查詢

where p.`city_id` = '1' and p.status = 'active' 
and p_i.display_order = '1' 
HAVING distance < 5
limit 0, 5

最后使用limit

您可以在limit之前添加having子句

select p.id, p.name, p_i.image as image, ( 3959 * acos( cos( radians(26.916279) )
 * cos( radians( lat ) ) * cos( radians( lng ) - radians(75.8082) )
 + sin( radians(26.916279) ) * sin( radians( lat ) ) ) ) AS distance 
 from `places` as p inner join `place_images` as p_i on p.`id` = p_i.`place_id`
 where p.`city_id` = '1' and p.status = 'active' and p_i.display_order = '1' 
 HAVING distance < 5 limit 0, 5
select p.id, p.name, p_i.image as image, ( 3959 * acos( cos( radians(26.916279) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(75.8082) ) + sin( radians(26.916279) ) * sin( radians( lat ) ) ) ) AS distance from `places` as p inner join `place_images` as p_i on p.`id` = p_i.`place_id` 
where p.`city_id` = '1' 
and p.status = 'active' 
and p_i.display_order = '1' 
HAVING distance < 5 # add this
limit 0, 5

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