[英]PHP htmlentities json string to android textview text
[英]Not able to print JSON object String in android TextView
所以我試圖從看起來像這樣的網站上獲取JSON字符串
[{"name":"Painting"},{"name":"Painting or varnishing doors"},{"name":"Painting or varnishing frames"},{"name":"Varnishing floors"},{"name":"Picking old wallpaper"},{"name":"Painting the facade"},{"name":"professional athlete"}]
我只想獲取帶有字符串“ Painting”的第一個JSONObject。
這是我的MainActivity.java代碼
package mobiletest.pixelapp.com.mobiletest;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.util.Log;
import android.widget.TextView;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.URL;
import java.net.URLConnection;
import model.Cup;
public class MainActivity extends AppCompatActivity {
private TextView textView;
private String myString;
private String anotherString;
private String myVar;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
textView = (TextView)findViewById(R.id.textView);
Cup myCup = new Cup();
String newString = myCup.myMethod();
try {
JSONArray jsonArray = new JSONArray(newString);
JSONObject jsonObject = jsonArray.getJSONObject(0);
Log.v("Key",jsonObject.getString("name"));
textView.setText(jsonObject.getString("name"));
} catch (JSONException e) {
e.printStackTrace();
}
}
}
這是我的Java類文件cup.java
package model;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.URL;
import java.net.URLConnection;
/**
* Created by pruthvi on 12/2/2015.
*/
public class Cup {
public String myMethod()
{
String output = getUrlContents("http://xyz.co/tests/android-query.php");
return output;
}
private static String getUrlContents(String theUrl)
{
StringBuilder content = new StringBuilder();
// many of these calls can throw exceptions, so i've just
// wrapped them all in one try/catch statement.
try
{
// create a url object
URL url = new URL(theUrl);
// create a urlconnection object
URLConnection urlConnection = url.openConnection();
// wrap the urlconnection in a bufferedreader
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));
String line;
// read from the urlconnection via the bufferedreader
while ((line = bufferedReader.readLine()) != null)
{
content.append(line + "\n");
}
bufferedReader.close();
}
catch(Exception e)
{
e.printStackTrace();
}
return content.toString();
}
}
現在的問題是,當我以Java運行此代碼時,我可以輕松地從JSONObject打印繪畫,但是當我嘗試通過為TextView設置文本來將其作為android視圖運行時,我得到了一些奇怪的系統。
12-02 14:06:26.809 19250-19250/mobiletest.pixelapp.com.mobiletest D/libc: [NET] getaddrinfo hn 10, servname NULL, ai_family 0+
12-02 14:06:26.809 19250-19250/mobiletest.pixelapp.com.mobiletest W/System.err: at java.net.InetAddress.lookupHostByName(InetAddress.java:393)
12-02 14:06:26.809 19250-19250/mobiletest.pixelapp.com.mobiletest W/System.err: at java.net.InetAddress.getAllByNameImpl(InetAddress.java:244)
12-02 14:06:26.809 19250-19250/mobiletest.pixelapp.com.mobiletest W/System.err: at java.net.InetAddress.getAllByName(InetAddress.java:219)
我是java和android的新手,到目前為止,我只想從遠程服務器文件和數據庫中獲取數據。
提前致謝
在onCrate方法中這樣做
try {
JSONArray jsonArray = new JSONArray(newString);
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject jsonObject = jsonArray.getJSONObject(i);
String name = jsonObject.getString("name")
textView.setText(name));}
} catch (JSONException e) {
e.printStackTrace();
}
它將名稱設置為textView。 樂於助人,樂於編碼
看這個例子,它會給你一個想法
AsyncTask<Void, Void, Void> asyncLoad = new AsyncTask<Void, Void, Void>()
{
@Override
protected Void doInBackground(Void... params)
{
URL url = new URL("http://www.omdbapi.com/?i=&t="
+ TITLE);
String URL2="http://www.omdbapi.com/?i=&t=saw";
Log.d("URL content", url.toString());
HttpURLConnection urlConnection = (HttpURLConnection) url
.openConnection();
Log.d("URL content", "register URL");
urlConnection.connect();
Log.d("URL connection", "establish connection");
return null;
}
@Override
protected void onPostExecute(Void result)
{
super.onPostExecute(result);
}
};
asyncLoad.execute();
您無法在UI線程中執行網絡任務。 所以
String newString = myCup.myMethod();
無法正常工作。
這些錯誤的主要原因與線程上下文有關。
如果要使用android執行網絡任務,請使用異步任務或其他網絡庫(我個人建議retrofit
)。
try
{
JSONArray jsonArray = new JSONArray(newString);
if(jarray.length()>0){
String name = jarray.getJSONObject(0).getString("name");
displayName(name); //new method
}catch(Exception e){
}
在onCreate()外部定義方法displayName(String )
public void displayName(final String name){
runOnUiThread(new Runnable() {
@Override
public void run() {
textView.setText(jsonObject.getString("name"));
}
});
}
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